Question

即时通讯使用mobitek gsm调制解调器，它使用的源代码在VB中。现在我想将代码转换为c＃。我遇到问题的代码是intModemStatus = SMS.ModemInit(frmModem.txtPort.Text, "")。之后，代码将通过以下选择案例进行：

intModemStatus = SMS.ModemInit(frmModem.txtPort.Text, "")

    Select Case intModemStatus

        Case 0
            FrmModem.txtText.Text = "GSM Modem Not Connected!"
            '[VB - Module1] frmModem.txtText = "GSM Modem Not Connected!"
            Exit Sub

        Case 1
            FrmModem.txtText.Text = "CONNECTED!"
            '[VB - Module1] frmModem.txtText = "GSM Modem Connected!"
            Exit Sub

        Case 2
            FrmModem.txtText.Text = "PIN Required!"
            '[VB - Module1] frmModem.txtText = "PIN Required!"
            Exit Sub

        Case 3
            FrmModem.txtText.Text = "Incorrect PIN Entered! Warning after 3 tries of incorrect PIN entered, your SIM card will be blocked by TELCO!"
            '[VB - Module1] frmModem.txtText = "Incorrect PIN entered! Warning: after 3 tries of incorrect PIN entered, your SIM card will be blocked by TELCO!"
            Exit Sub

        Case 4
            FrmModem.txtText.Text = "Your SIM card is blocked by TELCO!"
            '[VB - Module1] frmModem.txtText = "Your SIM card is blocked by TELCO!"
            Exit Sub

        Case 5
            FrmModem.txtText.Text = "Your SIM card has problem!"
            '[VB - Module1] frmModem.txtText = "Your SIM card has problem!"
            Exit Sub

        Case Else
            FrmModem.txtText.Text = "GSM Modem Not Connected!"
            '[VB - Module1] frmModem.txtText = "GSM Modem Not Connected!"
            Exit Sub

    End Select

我已将所有内容转换为c＃includes，其开关案例如下：

int ModemStatus = sms.ModemInit(txtPort.Text, "");
        switch (intModemStatus)
        {
            case 0:

                txtText.Text = "GSM Modem Not Connected!";
                //[VB - Module1] frmModem.txtText = "GSM Modem Not Connected!"
                return;

                break;
            case 1:
                txtText.Text = "CONNECTED!";
                //[VB - Module1] frmModem.txtText = "GSM Modem Connected!"
                return;


                break;
            case 2:
                txtText.Text = "PIN Required!";
                //[VB - Module1] frmModem.txtText = "PIN Required!"
                return;


                break;
            case 3:
                txtText.Text = "Incorrect PIN Entered! Warning after 3 tries of incorrect PIN entered, your SIM card will be blocked by TELCO!";
                //[VB - Module1] frmModem.txtText = "Incorrect PIN entered! Warning: after 3 tries of incorrect PIN entered, your SIM card will be blocked by TELCO!"
                return;


                break;
            case 4:
                txtText.Text = "Your SIM card is blocked by TELCO!";
                //[VB - Module1] frmModem.txtText = "Your SIM card is blocked by TELCO!"
                return;


                break;
            case 5:
                txtText.Text = "Your SIM card has problem!";
                //[VB - Module1] frmModem.txtText = "Your SIM card has problem!"
                return;


                break;
            default:
                txtText.Text = "GSM Modem Not Connected!";
                //[VB - Module1] frmModem.txtText = "GSM Modem Not Connected!"
                return;


                break;
        }

但是，我在使用此代码int ModemStatus = sms.ModemInit(txtPort.Text, "");时遇到问题。它说那个

参数1无法将字符串转换为short。 mobitekSMSAPI5.ModemInit（short，string）的最佳重载方法匹配有一些无效的参数。

然后我尝试更改int ModemStatus = sms.ModemInit(txtPort.Text, "");，但它说的相同。

使用mobitek gsm调制解调器，我需要添加MobitekSMSAPI5的参考，我做了。开关代码将确定调制解调器是否已连接或否则。

我真的希望有人能够加紧解决这个问题。我卡在中间，我不知道从哪里开始。任何种类的帮助表示赞赏。谢谢。

这是我的错误：当我使用此代码时，它出现：

 short port;
if (!short.TryParse(txtPort.Text, out port))
{
    throw new Exception("Failed to parse port");
    // or any other handling - depends on your needs
}

int ModemStatus = sms.ModemInit(port, "");

enter image description here

现在，当我更改下面的代码时，它会出现不同的错误。

enter image description here

Answer 1

sms.ModemInit接受short作为第一个参数。只要您处理VB.Net，就会隐式地将字符串转换为short。这可能是由于编译器的Option Strict选项，默认情况下禁用该选项。启用后，此选项仅允许隐式widening conversions。禁用时（默认状态），此选项允许隐式narrowing and widening conversions。

在C＃中，禁止缩小隐式转换，这就是您翻译的代码失败的原因。因此，您需要显式解析string值并将解析后的数字传递给方法：

short port = short.Parse(txtPort.Text);
int ModemStatus = sms.ModemInit(port, "");

或者更好的是，使用TryParse来避免可能的异常：

short port;
if (!short.TryParse(txtPort.Text, out port))
{
    throw new Exception("Failed to parse port");
    // or any other handling - depends on your needs
}

int ModemStatus = sms.ModemInit(port, "");

Answer 2

我会这样做：

short shortValue = 0;
if (short.TryParse(txtPort.Text, out shortValue))
{
    ... continue using shortValue
}
else
{
    ...Tell user the value must be a number
}

通过这种方式，您可以处理用户输入非数字的情况（无需借助异常）

Answer 3

你的问题只是一些铸造问题。第一个与端口号相关，ModemInit方法需要short值，但您传递string，因此您已使用short.TryParse修复了此问题。< / p>

另一个问题是你的返回类型，ModemInit方法似乎返回它自己的自定义enum值，如果所有你感兴趣的是整数值，那么你需要做的就是将其转换为int。

int ModemStatus = (int)sms.ModemInit(port, "");

Answer 4

由于错误明确指出，您不能将字符串作为短消息传递。

您需要致电short.Parse()。

将vb代码转换为c＃

4 个答案: