我需要使用前一行的值来生成累积值,如下所示。始终对于2000年的每个代码,起始基数为100。 我需要使用tsql代码来解决这个问题。
id Code Yr Rate Base
1 4 2000 5 100
2 4 2001 7 107 (100+7)
3 4 2002 4 111 (107+4)
4 4 2003 8 119 (111+8)
5 4 2004 10 129 (119+10)
6 5 2000 2 100
7 5 2001 3 103 (100+3)
8 5 2002 8 111 (103+8)
9 5 2003 5 116 (111+5)
10 5 2004 4 120 (116+4)
答案 0 :(得分:0)
行。我们有这样的表 CREATE Table MyTbl(id INT PRIMARY KEY IDENTITY(1,1),Code INT,Yr INT,Rate INT) 我们想通过Code计算累积值。 所以我们可以使用这样的查询:
1)递归(需要更多资源,但输出示例中的结果)
with cte as
(SELECT *, ROW_NUMBER()OVER(PARTITION BY Code ORDER BY Yr ASC) rn
FROM MyTbl),
recursion as
(SELECT id,Code,Yr,Rate,rn, CAST(NULL as int) as Tmp_base, CAST('100' as varchar(25)) AS Base FROM cte
WHERE rn=1
UNION ALL
SELECT cte.id,cte.Code,cte.Yr,cte.Rate,cte.rn,
CAST(recursion.Base as int),
CAST(recursion.Base+cte.Rate as varchar(25))
FROM recursion JOIN cte ON recursion.Code=cte.Code AND recursion.rn+1=cte.rn
)
SELECT id,Code,Yr,Rate,
CAST(Base as varchar(10))+ISNULL(' ('+ CAST(Tmp_base as varchar(10))+'+'+CAST(Rate as varchar(10))+')','') AS Base
FROM recursion
ORDER BY 1
OPTION(MAXRECURSION 0)
2)或者我们可以使用更快的查询而不使用递归。但结果是不可能生成像'107(100 + 7)'这样的字符串(只有像'107'这样的字符串)
SELECT *,
100 +
(SELECT ISNULL(SUM(rate),0) /*we need to calculate only the sum in subquery*/
FROM MyTbl AS a
WHERE
a.Code=b.Code /*the year in subquery equals the year in main query*/
AND a.Yr<b.Yr /*main feature in our subquery*/
) AS base
FROM MyTbl AS b