我有一个元素类型:
public class FieldInfo
{
public string Label { get; set; }
public string Value { get; set; }
}
我有一个充满FieldInfo
个对象的数组。
FieldInfo[] infos = new FieldInfo[]
{
new FieldInfo{Label = "label1", Value = "value1"},
new FieldInfo{Label = "label2", Value = "value2"}
};
现在我想将该数组转换为包含以下值的新数组:
string[] wantThatArray = new string[] {"label1", "value1", "label2", "value2"};
是否有一种简短的方法可以将infos
等数组转换为wantThatArray
之类的数组?
也许使用LINQ的Select?
答案 0 :(得分:10)
string[] wantThatArray = infos
.SelectMany(f => new[] {f.Label, f.Value})
.ToArray();
答案 1 :(得分:8)
我会保持简单:
string[] wantThatArray = new string[infos.Length * 2];
for(int i = 0 ; i < infos.Length ; i++) {
wantThatArray[i*2] = infos[i].Label;
wantThatArray[i*2 + 1] = infos[i].Value;
}
答案 2 :(得分:2)
与Marc Gravell的解决方案略有不同的变体
string[] wantThatArray = new string[infos.Length * 2];
for (int i = 0, k = 0; i < infos.Length; i++, k += 2) {
wantThatArray[k] = infos[i].Label;
wantThatArray[k + 1] = infos[i].Value;
}
答案 3 :(得分:0)
另一种变体:
string[] yourarray = infos.Select(x => string.Format("{0},{1}", x.Label, x.Value))
.Aggregate((x, y) => string.Format("{0},{1}", x, y))
.Split(',');
mhh但不好...... :(与其他人相比!
答案 4 :(得分:-1)
FieldInfo[,] infos = new FieldInfo[,]{
new FieldInfo{"label1", "value1"},
new FieldInfo{"label2", "value2"}
};
string[] to = infos.Cast<FieldInfo>().ToArray();
现在,您只需将to
转换为infos
。