Question

我想使用JAXB创建XML。它应该具有属性，其值必须来自相应类中定义的属性。

当前输出将属性作为子标记，而不是主标记中的属性。

我想要的XML的结构如下。

<?xml version="1.0" encoding="UTF-8"?>
<company>
    <department name="hr">
        <branch name="hr-recruitment">
            <manager> Manasa </manager>
            <phone>992222222</phone>
            <salary> 20000 </salary>
        </branch>
        <branch name="hr-finance">
            <manager> Sunder </manager>
            <phone>993333332</phone>
            <salary> 50000 </salary>
        </branch>
    </department>
    <department name="transport">
        <branch name="transport-employee">
            <manager> Raman </manager>
            <phone>888888888</phone>
            <salary> 30000 </salary>
        </branch>
        <branch name="transport-goods">
            <manager> Sheela </manager>
            <phone>99999999</phone>
            <salary> 75000 </salary>
        </branch>
    </department>
</company>

以下是标有JAXB注释的3个类：

1）company.class

@XmlRootElement(name = "tarang")
public class Company {

    private List<Department> listDepartments;

    public Company(List<Department> listDepartments) {
        this.listDepartments = listDepartments;
    }

    public Company() {

    }

    @XmlElementRef
    public List<Department> getListDepartments() {
        return listDepartments;
    }

    public void setListDepartments(ArrayList<Department> listDepartments) {
        this.listDepartments = listDepartments;
    }

}

2）Department.class

@XmlRootElement(name = "department")
public class Department {

    private String strDepartmentName;

    private List<Branch> listBranchs;

    public Department(String strDepartmentName, List<Branch> listBranchs) {
        this.strDepartmentName = strDepartmentName;
        this.listBranchs = listBranchs;
    }

    public Department() {

    }

    @XmlElement(name = "name")
    public String getStrDepartmentName() {
        return strDepartmentName;
    }

    public void setStrDepartmentName(String strDepartmentName) {
        this.strDepartmentName = strDepartmentName;
    }

    @XmlElementRef
    public List<Branch> getListBranchs() {
        return listBranchs;
    }

    public void setListBranchs(List<Branch> listBranchs) {
        this.listBranchs = listBranchs;
    }

}

3）Branch.class

@XmlRootElement(name = "branch")
public class Branch {

    private String strName;
    private String strManagerName;
    private String strPhone;
    private int intSalary;

    public Branch(String strName, String strManagerName, String strPhone,
            int intSalary) {
        this.strName = strName;
        this.strManagerName = strManagerName;
        this.strPhone = strPhone;
        this.intSalary = intSalary;
    }

    public Branch() {
        // TODO Auto-generated constructor stub
    }

    @XmlElement(name = "name")
    public String getStrName() {
        return strName;
    }

    public void setStrName(String strName) {
        this.strName = strName;
    }

    @XmlElement(name = "manager")
    public String getStrManagerName() {
        return strManagerName;
    }

    public void setStrManagerName(String strManagerName) {
        this.strManagerName = strManagerName;
    }

    @XmlElement(name = "phone")
    public String getStrPhone() {
        return strPhone;
    }

    public void setStrPhone(String strPhone) {
        this.strPhone = strPhone;
    }

    @XmlElement(name = "salary")
    public int getIntSalary() {
        return intSalary;
    }

    public void setIntSalary(int intSalary) {
        this.intSalary = intSalary;
    }

}

我目前的设计包含3个课程。

1）公司2）部门3）分公司

关系是：

1) class Company -has a- List of Departments.
2) class Department -has a- name (String).
3) class Department -has a- List of Branches.
4) class Branch -has a- name (String)
5) class Branch -has a- manager (String)
6) class Branch -has a- phone (String)
7) class Branch -has a- salary (String)

目前的输出是：

 <?xml version="1.0" encoding="UTF-8" standalone="yes"?>
    <tarang>
        <department>
            <branch>
                <salary>50000</salary>
                <manager>Manasa</manager>
                <name>hr-recruitment</name>
                <phone>999999999</phone>
            </branch>
            <branch>
                <salary>40000</salary>
                <manager>Sundar</manager>
                <name>hr-finance</name>
                <phone>888888888</phone>
            </branch>
            <name>hr</name>
        </department>
        <department>
            <branch>
                <salary>30000</salary>
                <manager>Raman</manager>
                <name>transport-employee</name>
                <phone>7777777777</phone>
            </branch>
            <branch>
                <salary>20000</salary>
                <manager>Sheela</manager>
                <name>transport-goods</name>
                <phone>6666666666</phone>
            </branch>
            <name>tranport</name>
        </department>
    </tarang>

部门名称和分支名称未作为属性附加。请建议我在类中进行更正，其中@xmlattribute注释必须应用于我以获得所需的输出。

Answer 1

@XmlAttribute应添加到您的Department课程中的字段声明中，如下所示：

@XmlAttribute(name = "name")
private String strDepartmentName;

有关XmlAttribute注释的更多详细信息，请参阅here。

使用JAXB创建具有属性和动态值的XML

1 个答案: