MySQL在多个表中计数并获得单个值

Question

想象：     t1 = 1     t2 = 3     t3 = 5

我需要在每张桌子上运行单独选择，并以一个数量报告计数，即：

 select * 
   from (select count(*) from t1)
          + (select count(*) from t2)
          + (select count(*) from t3);

我的最终结果应该是= 9

Answer 1

你很亲密;你可以写：

 select (select count(*) from t1)
        + (select count(*) from t2)
        + (select count(*) from t3)
 ;

Answer 2

select 
    (select count(*) from t1)
    + (select count(*) from t2)
    + (select count(*) from t3);