Question

表示例：

branch
----------------------------------
branchID | branchName | brMgrName|
----------------------------------
|      1  | a         |Tom       |
|      2  | b         |Jeff      |
|      3  | c         |Lin       |
----------------------------------

order
----------------------
orderID   | branchID |
----------------------
|   1     |     2   | 
|   2     |     2   | 
|   3     |     3   | 
----------------------


payment
--------------------------------
paymentID | orderID | p-amount |
--------------------------------
|   1     |     1   |   50.00  |
|   2     |     2   |  126.00  |
|   3     |     3   |   50.00  |
--------------------------------

我想要的输出是

-------------------------------------------
| branchName | brMgrName | Total Amount   |
-------------------------------------------
|      a     |  Tom      |     0.00       |
|      b     |  Jeff     |   252.00       |
|      c     |  Lin      |    50.00       |
-------------------------------------------

我试图确定如何在3个不同的表中总结每个分支的金额。

在输出中：
- branchName＆＃39; a＆＃39;没有来自订单表的任何价值，
- branchName＆＃39; b＆＃39;总结了paymentID 1＆amp; 2，与之相同 - branchName＆＃39; c＆＃39;

通过加入分支表和付款表，我已成功返回branchName和Total Amount：

SELECT `order`.branchID, sum(`p-amount`)
FROM `order`
JOIN payment
ON `order`.orderID = payment.orderID
GROUP BY branchID

但是当我尝试下面的代码时，它返回错误的值，只选择了1行。

SELECT branchName, brMgrName, sum(`p-amount`)
FROM branch, payment
JOIN (SELECT `order`.branchID, sum(`p-amount`)
      FROM `order`
      JOIN payment
      ON `order`.orderID = payment.orderID
      GROUP BY branchID) b
ON b.branchID = branchID;

非常感谢任何帮助。

Answer 1

试试这个：

SELECT b.branchName, brMgrName, sum(p.`p-amount`)
  FROM branch b
        LEFT JOIN `order` o
                ON b.branchID = o.branchID 
        LEFT JOIN payment p
                ON o.orderID = p.orderID 
GROUP BY b.branchName, brMgrName
ORDER BY 3 -- third column on select list

Answer 2

试试这个吗？

SELECT `branch`.`branchID`, `branch`.`branchName`, `branch`.`brMgrName`, SUM(`payment`.`p-amount`)
FROM `branch`
JOIN `order` ON `branch`.`branchID` = `order`.`branchID`
JOIN `payment` ON `order`.`orderID` = `payment`.`orderID`
GROUP BY `branch`.`branchID`

Answer 3

SELECT b.branchName,b.brMgrName,
ISNULL( (SELECT sum(p.pamount) FROM dbo.payment p   
WHERE p.orderID IN (SELECT o.orderid FROM dbo.[order] o
WHERE o.branchID=b. branchID)),0) FROM dbo.branch b

使用Subquery

获得多个表的总和

3 个答案: