Ruby Text Parsing：找到下一句的开头

Question

我的数据库中有一堆字符串，如下所示：

  

下班回家。那只狗从沙发上跳了起来   主人在门口。他舔脸干净。

字符串从句子中间开始。我想找个方法来切断最初的不完整的句子，然后从“从沙发上跳到门口的大师那里回来。他舔脸干净。”

我该怎么做？

Answer 1

问题是如何定义不完整的句子。我们可以假设所有以upcased字符开头的句子都是完整的句子。如果这样代码可能看起来像这样

str = 'driving home from work. The dog leaped of the sofa to great his master at the door. He licked his face clean.'
sentences = str.split('.')
sentences.shift if sentences[0][0].downcase == sentences[0][0]
sentences.join('.').strip << '.'

有点棘手但有效。

Answer 2

最简单的答案：

str = 'driving home from work. The dog leaped of the sofa to great his master at the door. He licked his face clean.'
str.sub!(/^[^A-Z].+?\./, '').strip!

Answer 3

https://github.com/ged/linkparser

这可能有所帮助。

Answer 4

这样的事可能吗？

str = "driving home from work. The dog leaped of the sofa to great his master at the door. He licked his face clean."
str.first == str.first.upcase ? str : str.split(".")[1..-1].join(".").lstrip << "."

假设它以大写字母开头表示句子的开头，否则就不可能。其他需要考虑的情况，如果以数字开头怎么办？例如：1只狗逃跑了。狗......是一只狗......一句话？