mySQL很多很多WHERE条件没有结果,cakephp分页

时间:2012-09-18 07:19:36

标签: mysql cakephp

我正在为CakePHP应用程序执行自定义分页规则。蛋糕分页创建的查询不会返回任何结果,我相信它应该。

表格如下:

projects ('id', 'project_leader_id'), 
users ('id', 'name'),
users_projects ('id', 'project_id', 'user_id')

projects many-many users_projects on project_id,
users many-many users_projects on user_id,
users one-many projects on project_leader_id

样本数据:

项目:

id (1), project_leader_id (1) 
id (2), project_leader_id (2)
id (3), project_leader_id (3)

用户:

id (1), name ("Peter")
id (2), name ("Joe")
id (3), name ("Mark")

users_projects:

id (1), project_id (1), user_id (2)
id (2), project_id (1), user_id (3)
id (3), project_id (2), user_id (1)
id (4), project_id (2), user_id (2)
id (5), project_id (3), user_id (3)
id (6), project_id (3), user_id (1)

我的查询:

SELECT Project.id, User.name
FROM projects AS Project
LEFT JOIN users_projects AS Assignment
    ON Project.id = Assignment.project_id
LEFT JOIN users AS User
    ON User.id = Assignment.user_id
WHERE Project.project_leader_id = 1
    OR Assignment.user_id = 1

它应返回3个结果,但不会返回任何结果。

分页结构如下:

$this->paginate = array(
'Project' => array(
    'joins' => array(
        array(
            'table' => 'users_projects', 
            'alias' => 'Assignment',
            'type' => 'LEFT',
            'conditions' => array(
                'Assignment.project_id' => 'Project.id',
            )
        )
    ),
    'conditions' => array(
        'OR' => array(
            'Assignment.user_id' => $this->Auth->User('id'),
            'Project.project_leader_id' => $this->Auth->User('id')
        )
    )
));

更新

查询仅返回WHERE条件中指定的包含Project.project_leader_id的项目,并且不考虑Assignment.user_id条件。

1 个答案:

答案 0 :(得分:0)

我发现了问题所在。 'join'键下的分页变量中的'conditions'子句必须在没有双箭头的情况下构造。

更改

'conditions' => array('Assignment.project_id' => 'Project.id')

'conditions' => array('Assignment.project_id = Project.id')

解决了这个问题。

初始查询如下所示:

LEFT JOIN `consultants_assignments` AS `consultantsAssignment` ON
(`consultantsAssignment`.`project_id` = `Project.id`) 

并在更改后:

LEFT JOIN `consultants_assignments` AS `consultantsAssignment` ON
(`consultantsAssignment`.`project_id` = `Project`.`id`)