我试图在CakePHP上做自定义分页,问题是我想传递自定义条件,如下所示:
$conditions['People'] = $this->People->find('all',
array(
'order' => array('People.id DESC'),
'limit' => 16,
'order' => 'People.id DESC'
)
);
$people = $this->paginate('People',$conditions);
基本上所有代码都涉及分页,但它不起作用,它会导致它找不到列人......
我只是想用自定义条件进行分页,也就是说,我想事先设置条件,有没有办法做到这一点?
答案 0 :(得分:4)
您是否看过文档?
根据文档,您应该添加以下条件:
public function list_recipes() {
$this->Paginator->settings = array(
'conditions' => array('Recipe.title LIKE' => 'a%'),
'limit' => 10
);
$data = $this->Paginator->paginate('Recipe');
$this->set(compact('data'));
}
所以猜这应该有效:
public function list_people() {
$this->Paginator->settings = array('order' => array('People.id DESC'),'limit' => 16,'order' => 'People.id DESC');
$data = $this->Paginator->paginate('People');
$this->set(compact('data'));
}
答案 1 :(得分:4)
这是我在蛋糕2.x
中的表现首先要确保在控制器中包含paginator组件和帮助器,例如
$public $components = array(
'Paginator'
);
$public $helpers = array(
'Paginator'
);
然后在你的行动中
$options = array(
'conditions' => array(
'Post.status' => 1
),
'fields' => array(
'Post.id',
'Post.title',
'Post.created'
),
'order' => array(
'Post.created' => 'DESC'
),
'limit' => 10
);
$this->Paginator->settings = $options;
$posts = $this->Paginator->paginate('Post');
答案 2 :(得分:3)
好的,我解决了,这就是我做的: 首先我声明了paginate,如果你想要它可以为空:
public $paginate = array('People'=>array(
'limit' => 6,
'order' => 'People.id DESC'
));
然后,每当我想要改变某些东西时,我就会这样做:
$this->paginate['People']['limit'] = 12;