我有如下表（产品）
id name quality weight
1 Demir-1 ST-1 10
2 Demir-2 ST-2 7
3 Demir-3 ST-1 20
4 Demir-2 ST-3 8
5 Demir-1 ST-3 6
6 Demir-4 ST-2 10
7 Demir-2 ST-2 12
8 Demir-1 ST-1 15
9 Demir-1 ST-3 10
10 Demir-3 ST-3 5
11 Demir-2 ST-2 5
现在，如果用户想要获得权重总和在20到25之间且name ='Result-2'的产品列表，那么结果应如下所示。所有组合必须显示在20到25之间的重量之和。
id name quality weight
4 Demir-2 ST-3 8
7 Demir-2 ST-2 12
11 Demir-2 ST-2 5
------------------------------
2 Demir-2 ST-2 7
4 Demir-2 ST-3 8
11 Demir-2 ST-2 5
------------------------------
------------------------------
1 Demir-1 ST-1 10
8 Demir-1 ST-1 15
你可以看到总和（重量）是25。
答案 0 :(得分：4)
DECLARE @tblProducts TABLE(Id INT IDENTITY, ProductName varchar(50),Quality varchar(50), ProductWeight int)
INSERT INTO @tblProducts SELECT 'Demir-1','ST-1',10
INSERT INTO @tblProducts SELECT 'Demir-2','ST-2',7
INSERT INTO @tblProducts SELECT 'Demir-3','ST-1',20
INSERT INTO @tblProducts SELECT 'Demir-2','ST-3',8
INSERT INTO @tblProducts SELECT 'Demir-1','ST-3',6
INSERT INTO @tblProducts SELECT 'Demir-4','ST-2',10
INSERT INTO @tblProducts SELECT 'Demir-2','ST-2' ,12
INSERT INTO @tblProducts SELECT 'Demir-1','ST-1',15
INSERT INTO @tblProducts SELECT 'Demir-1','ST-3',10
INSERT INTO @tblProducts SELECT 'Demir-3','ST-3' ,5
INSERT INTO @tblProducts SELECT 'Demir-2' ,'ST-2 ',5
;WITH Cte (Id,ProductQuality,ProductIds,ProductNames,ProductQualities,ProductTotalWeight,ProductWeights,ProductName1,ProductName2) AS
(
SELECT Id
,Quality
, ',' + CAST(Id AS VARCHAR(MAX))
,',' + CAST(ProductName AS VARCHAR(MAX))
,',' + CAST(Quality AS VARCHAR(MAX))
,ProductWeight
, ',' + CAST(ProductWeight AS VARCHAR(MAX))
,ProductName
,CAST(ProductName AS VARCHAR(MAX))
FROM @tblProducts
UNION ALL
SELECT p.Id
, p.Quality
,c.ProductIds + ',' + CAST(p.Id AS VARCHAR(MAX))
,c.ProductNames + ',' + CAST(p.ProductName AS VARCHAR(MAX))
,c.ProductQualities + ',' + CAST(p.Quality AS VARCHAR(MAX))
,c.ProductTotalWeight + p.ProductWeight
,c.ProductWeights + ',' + CAST(p.ProductWeight AS VARCHAR(MAX))
,p.ProductName
,c.ProductName2
FROM @tblProducts AS p JOIN Cte c ON p.Id < c.Id
WHERE p.ProductName = c.ProductName2
)
SELECT
ProductIds = STUFF(ProductIds,1,1,'')
,ProductNames = STUFF(ProductNames,1,1,'')
,ProductQualities = STUFF(ProductQualities,1,1,'')
,ProductTotalWeight
,ProductWeights = STUFF(ProductWeights,1,1,'')
FROM CTE
WHERE ProductTotalWeight BETWEEN 20 AND 25
<强>结果
ProductIds ProductNames ProductQualities ProductTotalWeight ProductWeights
3 Demir-3 ST-1 20 20
11,7,2 Demir-2,Demir-2,Demir-2 ST-2 ,ST-2,ST-2 24 5,12,7
11,7,4 Demir-2,Demir-2,Demir-2 ST-2 ,ST-2,ST-3 25 5,12,8
11,4,2 Demir-2,Demir-2,Demir-2 ST-2 ,ST-3,ST-2 20 5,8,7
10,3 Demir-3,Demir-3 ST-3,ST-1 25 5,20
9,1 Demir-1,Demir-1 ST-3,ST-1 20 10,10
9,8 Demir-1,Demir-1 ST-3,ST-1 25 10,15
8,1 Demir-1,Demir-1 ST-1,ST-1 25 15,10
8,5 Demir-1,Demir-1 ST-1,ST-3 21 15,6
7,4 Demir-2,Demir-2 ST-2,ST-3 20 12,8
答案 1 :(得分：2)
不幸的是，SQL不是正确的编码引擎，可以通过给定计算的表来提供所有组合，因为我一起黑客攻击的SQL代码显示。
通常我会建议这是用过程语言编写的，因为它的性质。 另请注意，此处的解决方案具有较大的输入数据集可能会快速耗尽SQL的递归限制。可能的产品数量也会增长到足够大的数量，而且运行速度非常慢。
drop table products
drop table #MinW
drop table #Products
go
create table products
(
id int,
name varchar(20),
quality varchar(20),
[weight] int
)
go
insert into products
select
1, 'Demir-1', 'ST-1', 10
union
select 2, 'Demir-2', 'ST-2', 7
union
select 3, 'Demir-3', 'ST-1', 20
union
select 4, 'Demir-2', 'ST-3', 8
union
select 5, 'Demir-1', 'ST-3', 6
union
select 6, 'Demir-4', 'ST-2', 10
union
select 7, 'Demir-2', 'ST-2', 12
union
select 8, 'Demir-1', 'ST-1', 15
union
select 9, 'Demir-1', 'ST-3', 10
union
select 10, 'Demir-3', 'ST-3', 5
union
select 11, 'Demir-2', 'ST-2', 5
go
select
p.id, p.name, p.quality, p.weight
into #MinW
from products p
inner join
(
select name,min(weight) as weight
from products group by name having min(weight) < 25
) as minW
on p.name = minW.name and p.weight = minW.weight
go
with weightProducts (id, name, [weight],history)
as
(
select id, name,[weight],convert(varchar(1024),'"'+convert(varchar(10),id)+'",') from #minW
union all
select products.id, products.name,products.[weight] + weightProducts.[weight],convert(varchar(1024),weightProducts.history+'"'+convert(varchar(10),products.id)+'",') from products, weightProducts where products.name = weightproducts.name and charindex('"'+convert(varchar(10),products.id)+'",',weightProducts.history)<=0 and (products.weight + weightProducts.weight) < 25
)
-- Statement using the CTE
select *
into #Products
from weightProducts
where weight between 20 and 25
go
select
p1.history,
p2.id,
p2.quality,
p2.weight,
p1.weight as totalWeight
from #Products p1
inner join
products p2 on p1.name = p2.name and charindex('"'+convert(varchar(10),p2.id)+'",',p1.history)>0
order by
p1.history,
p2.id
答案 2 :(得分：0)
SELECT * FROM tablename
WHERE name IN (
SELECT name FROM tablename
GROUP BY name
HAVING SUM(weight) BETWEEN 20 AND 25)
答案 3 :(得分：0)
这个查询怎么样：
select id, name, quality, weight from PRODUCTS
group by id, name, quality, weight
having sum(weight) between 20 and 25
答案 4 :(得分：0)
试试这个：
SELECT * FROM products
WHERE name IN (
SELECT name FROM products
GROUP BY name
HAVING SUM(weight) BETWEEN 20 AND 25)