Question

首先，这是我的代码：

s = raw_input("code: ")
s1 = " ".join(s.split()[::-1])
lists = s1.split()
for i in lists:
    if i.istitle() == True:
        print i

它目前的作用是反转一个字符串，如果以大写字母开头则打印一个单词。但问题是，如果一个单词就像“CApital”，它就不会打印出来。

让我举一些例子说明我希望该程序如何运作：

按相反顺序阅读
只关注消息中以单词开头的单词大写字母

如果这是输入的话：BaSe fOO ThE AttAcK 然后它应该返回：攻击基地

另一个例子：

code: soMe SuPPLies liKE Ice-cREAm aRe iMPORtant oNly tO THeir cReaTORS. tO DestroY thEm iS pOInTLess.
says: destroy their ice-cream supplies

非常感谢你！

Answer 1

您不需要istitle

if word[0].isupper():
    # do stuff

Answer 2

.istitle()仅在每个单词的首字母大写时才为真：

print 'MArk'.istitle()
print 'Mark'.istitle()  # True
print 'MARK'.istitle()
print 'marK'.istitle()
print 'Spam SPAM'.istitle()
print 'SPam Spam'.istitle()
print 'Spam Spam'.istitle() # True

所以只需测试第一个字母：

strings = [
    'BaSe fOO ThE AttAcK',
    'soMe SuPPLies liKE Ice-cREAm aRe iMPORtant oNly tO THeir cReaTORS. tO DestroY thEm iS pOInTLess']
for s in strings:
    print ' '.join(
        i for i in reversed(s.split()) if i[0].isupper()
        ).lower()

输出：

attack the base
destroy their ice-cream supplies

Answer 3

for i in lists:
    if i[0].isupper() and  i[1].islower():
        print i

Answer 4

你可以试试这个

s1 = s.split()[::-1]
for word in s1:
    if word[0].istitle() is True:
        out_list.append(word.lower())
print " ".join(out_list)

或更复杂但更短的版本

print " ".join(map(str.lower, filter(lambda x:x[0].istitle(), s.split()[::-1])))

棘手的谜题，中途！读大写字母

4 个答案: