我真的可以使用一些指导如何将这个SQL查询带到NHibernate QueryOver。我尝试使用Linq,因为我对Linq更熟悉。我们正在研究的项目是使用QueryOver,所以最好现在就保持这条路线。
工作SQL查询:将DateTime重绕为1分钟并正确分组/排序/计数......
select dateadd(minute,(datediff(minute,0,dateTimeColumn)/1)*1,0), COUNT(*)
from PartData
group by dateadd(minute,(datediff(minute,0,dateTimeColumn)/1)*1,0)
order by dateadd(minute,(datediff(minute,0,dateTimeColumn)/1)*1,0)
返回预期结果:
2012-08-31 00:00:00.000, 3
2012-08-31 00:01:00.000, 4
2012-08-31 00:02:00.000, 3
2012-08-31 00:03:00.000, 3
2012-08-31 00:04:00.000, 4
2012-08-31 00:05:00.000, 3
2012-08-31 00:06:00.000, 3
2012-08-31 00:07:00.000, 4
2012-08-31 00:08:00.000, 3
修改
我越来越近了......
private IQueryOver<entities.PartData, entities.PartData> PartPerHourQuery(ISession session)
{
return session.QueryOver<entities.PartData>()
.Select(
Projections.Alias(
Projections.GroupProperty(
Projections.SqlFunction(
new SQLFunctionTemplate(NHibernateUtil.DateTime, "DateAdd(mm,1,Date)"),
NHibernateUtil.DateTime, _partsDate))
, "Date"),
Projections.Alias(Projections.RowCount(), "Count"))
.TransformUsing(Transformers.AliasToBean<entities.PartsPerHour>());
}
产生以下SQL:
SELECT DateAdd(mm,1,dateTimeColumn), count(*)
FROM [PartData]
GROUP BY DateAdd(mm,1,dateTimeColumn)
只需要弄明白如何在那里找到日期:)
答案 0 :(得分:7)
通过坚持不懈的力量,我成功赢得了这场战斗。这是我上面提到的SQL查询的QueryOver ......我相信我已经在这个NHibernate的事情上转了一个角落:)
非常感谢任何改进或替代方法重新产生预期结果的建议。
private IQueryOver<entities.PartData, entities.PartData> PartPerHourQuery(ISession session)
{
return session.QueryOver<entities.PartData>()
.Select(
Projections.Alias(
Projections.GroupProperty(
Projections.SqlFunction(
new SQLFunctionTemplate(NHibernateUtil.DateTime, "DateAdd(minute," +
new SQLFunctionTemplate(
NHibernateUtil.DateTime,
"(DateDiff(minute, 0, Date)/1)*1") +
",0)"),
NHibernateUtil.DateTime, _partsDate))
, "Date"),
Projections.Alias(Projections.RowCount(), "Count"))
.TransformUsing(Transformers.AliasToBean<entities.PartsPerHour>());
}