Question

我正在使用密钥“rubicon”加密“06.93308”，首先使用javax.crypto.spec.SecretKeySpec，另一个使用openSSL在C ++中加密。但是两者都给了我不同的加密值。 java版本给我十六进制A834BDD6C3478B8C，而OpenSSL给我D06D7CB756744903这是非常不同的。目的是获得与java等价物相同的结果。关于我做错了什么想法？

java代码如下：

char[] password = new char[] { 'r', 'u', 'b', 'i', 'c', 'o', 'n' };
byte[] raw = encrypt(password,"06.93308" );

    private static byte[] encrypt(char[] password, String plaintext) throws Exception {
            byte[] bytes = new byte[password.length];
            for (int i = 0; i < password.length; ++i) {
                    bytes[i] = (byte) password[i];
            }
            SecretKeySpec skeySpec = new SecretKeySpec(bytes, "Blowfish");
            Cipher cipher = Cipher.getInstance("Blowfish/ECB/NoPadding");
            cipher.init(Cipher.ENCRYPT_MODE, skeySpec);
            byte[] encrypted = cipher.doFinal(plaintext.getBytes());
            return encrypted;
    }

c ++方面如下：

   CBlowFish oBlowFish((byte *)"rubicon", 8);

   char encryptedPrice[17] = "\0\0\0\0\0\0\0\0";
   char myBidPrice[] = "06.93308";
   encrypt(myBidPrice,encryptedPrice);


    void encrypt(char bidPrice[],char encryptedPrice[])
    {
        oBlowFish.Encrypt((unsigned char*)bidPrice, (unsigned char*)encryptedPrice,8 );
    }

这是openSSL代码，它给出了与上述C ++代码相同的结果

#define SIZE 16

unsigned char *out = (unsigned char *)calloc(SIZE+1, sizeof(char));
BF_KEY *key = (BF_KEY *)calloc(1, sizeof(BF_KEY));
BF_set_key(key, SIZE, (const unsigned char*)"rubicon" );
BF_ecb_encrypt(in, out, key, BF_ENCRYPT);
printf("%s\n",out);

Answer 1

“rubicon”不是16个字节长。您必须相应地调整SIZE。

为什么我看到两个河豚实施之间的不一致？

1 个答案: