Question

创建TracReports有很多例子。 This仍然是一个棘手的问题，我所知道的任何现有食谱都没有涵盖：

...设计报告以显示用户所在的所有门票所有者，记者或他们没有创建的门票，但他们是门票已发表评论。这是最后一个棘手的部分。

任何指针，考虑到有效性作为额外奖励？

Answer 1

这是我的第一个自己的工作解决方案：

“（当前）用户是所有者或记者或（其中一位）评论作者”

SELECT
  p.value AS __color__,
  t.milestone AS __group__,
  id AS ticket, t.type AS type,
  reporter, t.time as created,
  owner, changetime AS modified,
  author as commenter, tcg.time as date
FROM ticket t
LEFT JOIN enum p ON p.name = t.priority AND p.type = 'priority'
LEFT JOIN ticket_change tcg ON t.id = tcg.ticket
WHERE owner = $USER OR reporter = $USER
GROUP BY id

UNION

SELECT
  p.value AS __color__,
  t.milestone AS __group__,
  id AS ticket, t.type AS type,
  reporter, t.time as created,
  owner, changetime AS modified,
  author as commenter, tcg.time as date
FROM ticket t
LEFT JOIN enum p ON p.name = t.priority AND p.type = 'priority'
LEFT JOIN ticket_change tcg ON t.id = tcg.ticket
WHERE author = $USER
  AND id NOT IN (
  SELECT id
  FROM ticket
  WHERE owner = $USER OR reporter = $USER
)
GROUP BY id
ORDER BY t.milestone, p.value, t.type, t.time

我绝不是SQL大师，所以可能会有一个更有效的解决方案，但是这个解决方案至少可以显示评论的票证，而且每张票证不会超过一次。

如何创建包含用户已触及或负责的所有故障单的Trac报告？

1 个答案: