Question

我在这里得到了这些查询字符串......

SELECT 
    c.clientid, c.clientname, c.billingdate, 
    i.total - (select ifnull(sum(p.amount), 0) from payment p 
               where p.invoice = i.invoiceid Order by i.invoiceid) AS remaining 
FROM 
    client c 
INNER JOIN 
    invoice i 
WHERE 
    c.clientid = i.client 
ORDER BY 
    clientname

它的作用是，它获取所有客户的清单，他们的开票日期和余额。我还为客户开具发票，每张发票都有余额。我想要做的是为每个客户端获取客户最新的剩余余额（具有最高id值的发票）。

我所查询的内容是每个客户多次列出每个客户的每个剩余余额......就像这样

client 1 0.00
client 1 1.00
client 1 3.00

我正在寻找的是

client 1 0.00
client 2 3.00
client 3 5.00

我希望我有意义。我也试过Order by MAX(i.invoiceid)，但只返回一个客户端。

Answer 1

我不确定为什么max invoiceid不适合你

SELECT 
    c.clientid, c.clientname, c.billingdate, 
    i.total - (select ifnull(sum(p.amount), 0) from payment p 
               where p.invoice = i.invoiceid Order by i.invoiceid) AS remaining 
FROM 
    client c 
INNER JOIN 
    invoice i 
WHERE 
    c.clientid = i.client 
AND i.invoiceid = (SELECT MAX(i2.invoiceid) FROM invoice i2 WHERE i2.client = i.client) 
ORDER BY 
    clientname

现在您应该只获取客户最新发票

Answer 2

试试这个：

SELECT c.clientid, c.clientname, c.billingdate, i.total - 
(select ifnull(sum(p.amount), 0) from payment p where p.invoice = i.invoiceid Order by i.invoiceid DESC LIMIT 1) AS remaining 
FROM client c inner join invoice i where c.clientid = i.client ORDER BY clientname

使用DESCending订单和LIMIT 1，您将只为每个客户选择一个金额，ID最高的金额（因此是最新的）

SQL Max获得最高ID

2 个答案: