当我从Java打开websocket服务器应用程序的websocket连接时,服务器会看到两个连接。第一个从不发送任何数据,第二个发送所有正确的标题,等等。任何人都知道这是什么原因?
客户端连接是:
var websocket = new WebSocket( "ws://192.168.1.19:3333/websession" );
在服务器端,在while循环中,我调用“serverSocket.accept()”,然后调用两次。但是其中一个从不发送任何数据(in.read()最终只是在没有返回任何内容的情况下超时)。
JAVA服务器代码
import java.net.*;
import java.io.*;
import java.security.*;
public class WebListener {
public static void main(String[] args) throws Exception {
ServerSocket serverSocket = null;
boolean listening = true;
try {
serverSocket = new ServerSocket(4444);
} catch (IOException e) {
System.err.println("Could not listen on port: 4444.");
System.exit(-1);
}
while (listening) new ServerThread(serverSocket.accept()).start();
serverSocket.close();
}
}
class ServerThread extends Thread {
private Socket socket = null;
public ServerThread(Socket socket) {
super("ServerThread");
this.socket = socket;
}
public void run() {
try {
OutputStream outStream = null;
PrintWriter out = new PrintWriter( outStream = socket.getOutputStream(), true);
BufferedReader in = new BufferedReader( new InputStreamReader( socket.getInputStream()));
String inputLine, outputLine;
//Handle the headers first
doHeaders( out, in );
// ..elided..
out.close();
in.close();
socket.close();
} catch (Exception e) {
e.printStackTrace();
}
}
public void doHeaders(PrintWriter out, BufferedReader in) throws Exception {
String inputLine = null;
String key = null;
//Read the headers
while ( ( inputLine = in.readLine() ) != null ) {
//Get the key
if ( inputLine.startsWith( "Sec-WebSocket-Key" ) )
key = inputLine.substring( "Sec-WebSocket-Key: ".length() );
//They're done
if ( inputLine.equals( "" ) ) break;
}
//We need a key to continue
if ( key == null ) throw new Exception( "No Sec-WebSocket-Key was passed!" );
//Send our headers
out.println( "HTTP/1.1 101 Web Socket Protocol Handshake\r" );
out.println( "Upgrade: websocket\r" );
out.println( "Connection: Upgrade\r" );
out.println( "Sec-WebSocket-Accept: " + createOK( key ) + "\r" );
out.println( "\r" );
}
public String createOK(String key) throws NoSuchAlgorithmException, UnsupportedEncodingException, Exception {
String uid = "258EAFA5-E914-47DA-95CA-C5AB0DC85B11";
String text = key + uid;
MessageDigest md = MessageDigest.getInstance( "SHA-1" );
byte[] sha1hash = new byte[40];
md.update( text.getBytes("iso-8859-1"), 0, text.length());
sha1hash = md.digest();
return new String( base64( sha1hash ) );
}
public byte[] base64(byte[] bytes) throws Exception {
ByteArrayOutputStream out_bytes = new ByteArrayOutputStream();
OutputStream out = new Base64.OutputStream(out_bytes); //Using http://iharder.net/base64
out.write(bytes);
out.close();
return out_bytes.toByteArray();
}
private String convertToHex(byte[] data) {
StringBuffer buf = new StringBuffer();
for (int i = 0; i < data.length; i++) {
int halfbyte = (data[i] >>> 4) & 0x0F;
int two_halfs = 0;
do {
if ((0 <= halfbyte) && (halfbyte <= 9))
buf.append((char) ('0' + halfbyte));
else
buf.append((char) ('a' + (halfbyte - 10)));
halfbyte = data[i] & 0x0F;
} while(two_halfs++ < 1);
}
return buf.toString();
}
}
答案 0 :(得分:1)
这看起来是Firefox的一个错误。在Chrome中,它只会打开一个连接,而Firefox 15中的同一页面会打开两个连接。