Question

我有以下lambda表达式：

string queryToken = queryTokens.Last();
var result = from locationAddress in locations
             let tokens = GetLetterTokens(locationAddress.Name)
             let distance = (from token in tokens
                             where token.Contains(queryToken, StringComparison.OrdinalIgnoreCase)
                             select token.Length - queryToken.Length).Min()
             orderby distance
             select new
                        {
                            LocationAddress = locationAddress,
                            LocationDistance = distance,
                        };

它写的是什么并不重要。有时在计算distance时，没有tokens包含queryToken，因此无法返回.Min()。如何跳过这些案例？我不想将它们添加到result变量中。

Answer 1

听起来你只是想要：

let tokens = ...
where tokens.Any(token.Contains(queryToken, StringComparison.OrdinalIgnoreCase))
let distance = ...

或者，只需在选择令牌时进行过滤，然后检查是否存在：

var result = from locationAddress in locations
             let tokens = GetLetterTokens(locationAddress.Name)
                              .Where(token => token.Contains(queryToken, StringComparison.OrdinalIgnoreCase)
             where tokens.Any()
             let distance = tokens.Min(token => token.Length - queryToken.Length)

当'let'无法在lambda表达式中计算时，跳过添加元素

1 个答案: