重新编辑

Question

;WITH n AS  
( 
  SELECT problemID, StationName, problemCode, ProblemCreateDate, probCount, 
    c = COUNT(*) OVER (PARTITION BY StationName, problemCode), 
    rn = ROW_NUMBER() OVER  
    ( 
      PARTITION BY StationName, problemCode ORDER BY ProblemCreateDate DESC, problemID DESC 
    ) 
  FROM dbo.tblProblems
) 
 SELECT problemID, StationName, problemCode, ProblemCreateDate, c 
 FROM n WHERE rn = 1;

还有另一个名为tblCustomers的表，其中列isAssistent类型（bit）

我尝试进行内连接，但对我来说太复杂了，在尝试应用inner join的过滤器时遇到错误

tblCustomers where tblCustomers.isAssistent =1

我将非常感激并且很高兴知道如何编写正确的语法

重新编辑

inner join tblCustomers on tblProblems.CustID = tblCustomers.custID

错误，我最后一次尝试

消息4104，级别16，状态1，行14多部分标识符＆＃34; tblProblems.CustID＆＃34;无法受约束。 Msg 4104，Level 16，State 1，第12行多部分标识符＆＃34; tblproblems.problemID＆＃34;不可能界。消息4104，级别16，状态1，行12多部分标识符＆＃34; tblproblems.custID＆＃34;无法受约束。 Msg 4104，Level 16，State 1，第12行多部分标识符＆＃34; tblproblems.StationName＆＃34;不能约束。消息4104，级别16，状态1，行12多部分标识符＆＃34; tblproblems.problemCode＆＃34;无法受约束。消息4104， 16级，状态1，12行多部分标识符＆＃34; tblproblems.ProblemCreateDate＆＃34;无法受约束。

这是我做的疯狂猜测：

;WITH n AS  
( 
  SELECT tblCustomers.*,tblproblems.problemID, tblproblems.StationName, tblproblems.problemCode, tblproblems.ProblemCreateDate, tblproblems.probCount, 
    c = COUNT(*) OVER (PARTITION BY tblproblems.StationName, tblproblems.problemCode), 
    rn = ROW_NUMBER() OVER  
    ( 
      PARTITION BY tblproblems.StationName, tblproblems.problemCode ORDER BY tblproblems.ProblemCreateDate DESC, tblproblems.problemID DESC 
    ) 
  FROM dbo.tblProblems
  inner join tblCustomers on tblProblems.CustID = tblCustomers.custID
) 
SELECT tblCustomers.*, tblproblems.problemID, tblproblems.custID, tblproblems.StationName, tblproblems.problemCode, tblproblems.ProblemCreateDate, c 
FROM n 
inner join tblCustomers on tblProblems.CustID = tblCustomers.custID
WHERE rn = 1;

目的是仅在tblCustomers.isAssistent = 1时选择tblProblems的结果

Answer 1

您在外面的查询是错误的，应该是

SELECT tblCustomers.*, n.problemID, n.custID, 
           n.StationName, n.problemCode, n.ProblemCreateDate, c 
FROM n 
inner join tblCustomers on n.CustID = tblCustomers.custID
WHERE rn = 1;

为什么你再次加入tblcustomers？

你可以这样做：

;WITH n AS  

( 
  SELECT tblCustomers.*,tblproblems.problemID, tblproblems.StationName, 
         tblproblems.problemCode, tblproblems.ProblemCreateDate,
         tblproblems.probCount, 
    c = COUNT(*) OVER 
        (PARTITION BY tblproblems.StationName, tblproblems.problemCode), 
    rn = ROW_NUMBER() OVER  
    ( 
      PARTITION BY tblproblems.StationName, tblproblems.problemCode
      ORDER BY tblproblems.ProblemCreateDate DESC, tblproblems.problemID DESC 
    ) 
  FROM dbo.tblProblems
  inner join tblCustomers on tblProblems.CustID = tblCustomers.custID
  WHERE tblCustomers.isAssistent =1

) 
SELECT n.* FROM n where rn = 1

如果您只需要问题数据

;WITH n AS  

( 
  SELECT tblproblems.problemID, tblproblems.StationName, 
         tblproblems.problemCode, tblproblems.ProblemCreateDate,
         tblproblems.probCount, 
    c = COUNT(*) OVER 
        (PARTITION BY tblproblems.StationName, tblproblems.problemCode), 
    rn = ROW_NUMBER() OVER  
    ( 
      PARTITION BY tblproblems.StationName, tblproblems.problemCode
      ORDER BY tblproblems.ProblemCreateDate DESC, tblproblems.problemID DESC 
    ) 
  FROM dbo.tblProblems
  inner join tblCustomers on tblProblems.CustID = tblCustomers.custID
  WHERE tblCustomers.isAssistent =1

) 
SELECT n.* FROM n where rn = 1

sql inner使用Count（）和窗口函数进行连接

重新编辑

1 个答案: