Question

在以下数据框中，“时间”列为character

id<-c(1,2,3,4)
time<-c("00:00:01","01:02:00","09:30:01","14:15:25")
df<-data.frame(id,time)

我想知道如何将其转换为time，以便我可以对其进行算术计算。

Answer 1

使用包chron中的chron功能：

time<-c("00:00:01", "01:02:00", "09:30:01", "14:15:25")

library(chron)
x <- chron(times=time)

x
[1] 00:00:01 01:02:00 09:30:01 14:15:25

做一些有用的事情，比如计算连续元素之间的差异：

diff(x)
[1] 01:01:59 08:28:01 04:45:24

chron个对象在内部将值存储为每天几分之一秒。因此，1秒相当于1/(60*60*24)或1/86400，即1.157407e-05。

所以，为了增加时间，一个简单的选择就是：

x + 1/86400
[1] 00:00:02 01:02:01 09:30:02 14:15:26

Answer 2

使用base R你可以将它转换为类POSIXct的对象，但这确实会为时间添加一个日期：

id<-c(1,2,3,4)
time<-c("00:00:01","01:02:00","09:30:01","14:15:25")
df<-data.frame(id,time,stringsAsFactors=FALSE)

as.POSIXct(df$time,format="%H:%M:%S")
[1] "2012-08-20 00:00:01 CEST" "2012-08-20 01:02:00 CEST"
[3] "2012-08-20 09:30:01 CEST" "2012-08-20 14:15:25 CEST"

但这确实允许你对它们进行算术运算。

Answer 3

另一种可能的替代方案可能是：

time <- c("00:00:01","01:02:00","09:30:01","14:15:25")
converted.time <- as.difftime(time, units = "mins") #"difftime" class
secss <- as.numeric(converted.time, units = "secs")
hourss <- as.numeric(converted.time, units = "hours")
dayss <- as.numeric(converted.time, units="days")

甚至：

w <- strptime(x = time, format = "%H:%M:%S") #"POSIXlt" "POSIXt" class

Answer 4

lubridate在时间格式上提供了很好的灵活性：

library(lubridate)

time_hms_1<-c("00:00:01", "01:02:00", "09:30:01", "14:15:25")
hms(time_hms_1)
#> [1] "1S"          "1H 2M 0S"    "9H 30M 1S"   "14H 15M 25S"


time_hms_2<-c("0:00:01", "1:02:00", "9:30:01", "14:15:25")
hms(time_hms_2)
#> [1] "1S"          "1H 2M 0S"    "9H 30M 1S"   "14H 15M 25S"

time_hm_1<-c("00:00", "01:02", "09:30", "14:15")
hm(time_hm_1)
#> [1] "0S"         "1H 2M 0S"   "9H 30M 0S"  "14H 15M 0S"

time_hm_2<-c("0:00", "1:02", "9:30", "14:15")
hm(time_hm_2)
#> [1] "0S"         "1H 2M 0S"   "9H 30M 0S"  "14H 15M 0S"

^{由reprex package（v0.3.0）于2020-07-03创建}

Answer 5

还可以使用hms软件包。

id <- c(1, 2, 3, 4)
time <- c("00:00:01", "01:02:00", "09:30:01", "14:15:25")
df <- data.frame(id, time, stringsAsFactors = FALSE)

将列time转换为类hms

# install.packages("hms")
library(hms)
df$time <- as.hms(df$time)

执行算术计算

diff(df$time)
#01:01:59
#08:28:01
#04:45:24

Answer 6

使用ITime包中的data.table类：

ITime是一天中的时间类，存储为一天中的整数秒数。

library(data.table)
(it <- as.ITime(time))
# [1] "00:00:01" "01:02:00" "09:30:01" "14:15:25"

it + 10
# [1] "00:00:11" "01:02:10" "09:30:11" "14:15:35"


diff(it)
# [1] "01:01:59" "08:28:01" "04:45:24"

在R中将字符转换为时间

6 个答案: