我想将natification消息发送到我的设备但是有这个错误
com.google.android.gcm.server.InvalidRequestException: HTTP Status Code: 404
我不确定为什么。
这是我的代码
package com.avilyne.gcm;
import java.io.IOException;
import java.util.ArrayList;
import java.util.List;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import com.google.android.gcm.server.Message;
import com.google.android.gcm.server.MulticastResult;
import com.google.android.gcm.server.Sender;
public class GCMBroadcast extends HttpServlet {
private static final String myApiKey = "AIzaSyAHUdHy-7o-XJS59mhAzUUoTqn-EUb9s88";
private static final String regID = "APA91bHUcUuv3ViHfIkZg7YyKeiq3Ta1WVqEWrdIs9AZwdQ2nfSA2r-9BcH4WxRnAb0mHXEqEi7WMngPKQyrzcP5EhCFLqsprJpscHLIyi8gK80SdMpHluLBk3iRUCQTShY8szNvy3f4IBiGZv75ioe-Ai8wnZLqKw";
private List<String> androidTargets = new ArrayList<String>();
private static final long serialVersionUID = 1L;
public GCMBroadcast() {
super();
androidTargets.add(regID);
}
/*protected void doGet(HttpServletRequest req, HttpServletResponse resp)
throws ServletException, IOException {
doPost( req, resp);*/
@Override
protected void doPost(HttpServletRequest req, HttpServletResponse resp)
throws ServletException, IOException {
String userMessage = "";
userMessage = req.getParameter("Message");
Sender sender = new Sender(myApiKey);
Message message = new Message.Builder().addData("Message", userMessage)
.build();
MulticastResult result = sender.send(message, androidTargets, 1);
if (result.getResults() != null) {
int canonicalRegId = result.getCanonicalIds();
if (canonicalRegId != 0) {
}
} else {
int error = result.getFailure();
System.out.println("Broadcast failure: " + error);
}
req.setAttribute("Message", userMessage);
req.getRequestDispatcher("index.jsp").forward(req, resp);
}
}
当不使用doGet方法尝试此代码时，返回“HTTP状态405 - 此URL不支持HTTP方法GET”此错误。 İfı添加doGet方法并在doGet中调用doPost方法。它返回“HTTP状态500 - HTTP状态代码：404（未找到
我尝试将消息发送到服务器时收到的完整错误消息是：
com.google.android.gcm.server.InvalidRequestException: HTTP Status Code: 404(<HTML>
<HEAD>
<TITLE>Not Found</TITLE>
</HEAD>
<BODY BGCOLOR="#FFFFFF" TEXT="#000000">
<H1>Not Found</H1>
<H2>Error 404</H2>
</BODY>
</HTML>)
at com.google.android.gcm.server.Sender.sendNoRetry(Sender.java:367)
at com.google.android.gcm.server.Sender.send(Sender.java:261)
at com.avilyne.gcm.GCMBroadcast.doPost(GCMBroadcast.java:49)
at com.avilyne.gcm.GCMBroadcast.doGet(GCMBroadcast.java:35)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:621)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:722)
at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:305)
at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:210)
at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:225)
at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:123)
at org.apache.catalina.authenticator.AuthenticatorBase.invoke(AuthenticatorBase.java:472)
at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:168)
at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:98)
at org.apache.catalina.valves.AccessLogValve.invoke(AccessLogValve.java:927)
at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:118)
at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:407)
at org.apache.coyote.http11.AbstractHttp11Processor.process(AbstractHttp11Processor.java:1001)
at org.apache.coyote.AbstractProtocol$AbstractConnectionHandler.process(AbstractProtocol.java:585)
at org.apache.tomcat.util.net.JIoEndpoint$SocketProcessor.run(JIoEndpoint.java:310)
at java.util.concurrent.ThreadPoolExecutor.runWorker(Unknown Source)
at java.util.concurrent.ThreadPoolExecutor$Worker.run(Unknown Source)
at java.lang.Thread.run(Unknown Source)
我不知道为什么我会收到这个错误。有人可以帮忙吗？该文档没有说明404代码。
这是web.xml代码;
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" id="WebApp_ID" version="3.0">
<servlet>
<servlet-name>GCMBroadcast</servlet-name>
<servlet-class>com.avilyne.gcm.GCMBroadcast</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>GCMBroadcast</servlet-name>
<url-pattern>/GCMBroadcast</url-pattern>
</servlet-mapping>
<welcome-file-list>
<welcome-file>index.jsp</welcome-file>
</welcome-file-list>
</web-app>
那就是index.jsp代码;
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<%
// retrieve our passed CollapseKey and Message parameters, if they exist.
String message = "Generic Broadcast Message";
Object msgObj = request.getAttribute("Message");
if (msgObj != null) {
message = msgObj.toString();
}
%>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<title>Android GCM Broadcast</title>
</head>
<body>
<h2>GCM Broadcast Demo</h2>
<form action="GCMBroadcast" method="post">
<label>Broadcast Message </label>
<br/><textarea name="Message" rows="3" cols="60" ><%=message %> </textarea>
<br/><input type="submit" name="submit" value="Submit" />
</form>
</body>
</html>
答案 0 :(得分：2)
发布发件人类的代码。但很可能你的GCM服务器的URL错误。它应该是一个HTTPS POST请求：
https://android.googleapis.com/gcm/send
答案 1 :(得分：1)
当我尝试通过GCM发送消息时，我遇到了同样的错误（我是用PHP做的，但我觉得这不重要。）
以下是我的问题的链接：
Google GCM server returns 404 error
我已经发现了我的问题（并回答了我自己的问题:)）。 每次我尝试将空值传递给GCM时都会出现错误。我用空字符串替换了null，一切都很好。我不知道为什么，文档没有说明这个问题，但就是这样。
因此，这可能是您收到此错误的原因，或者您可能只是链接到GCM服务器的错误。
答案 2 :(得分：0)
Google提供的com.google.android.gcm.server.Sender类中嵌入了URL。最好的选择可能是通过Eclipse调试会话逐步执行doPost（）以查看错误是实际发生在sender.send（）时刻，还是发生在result.getResults（）时刻或之前的某个地方。
可能是在这些点之前发生了错误（正确传递了“Message”和“CollapseKey”值？），并且只是稍后在进程中被捕获，为您提供了所看到的堆栈跟踪。 / p>