我希望有人可以提供帮助,因为我现在已经尝试解决这个问题一段时间了,而且还遇到了一个非常小的问题。
通过以下查询,我主要尝试执行以下操作:
从订单中选择所有股票代码。
然后,找到每个股票代码存储在STOCK_LOCATIONS表中的所有位置。
然后,从STOCK_LOCATIONS表中返回一个位置。
但是,我需要交叉引用LOCATION_DATA表。 LOCATION_DATA表中的每个位置都有一个名为PICK的列,包含Y或N.我想返回Y为首选的位置,如果PICK列中没有Y,则返回N.
我实际上需要在Inner Join LOCATION_DATA查询中对结果进行排序,但这是不可能的。我已经尝试在INNER JOIN中添加一个SELECT语句(我认为这可能是最好的方法),但未能使它工作。
任何建议表示赞赏。 非常感谢...
SELECT
STOCK_LOCATIONS.*,
LOCATION_DATA.*,
STOCK_DATA.PHYSICAL,
ORDER_DATA.ENTRY,
ORDER_DATA.STOCK,
ORDER_DATA.ORDER_QTY,
(SELECT
COUNT(STOCK_LOCATIONS.location)
FROM STOCK_LOCATIONS
WHERE ORDER_DATA.STOCK = STOCK_LOCATIONS.sku
GROUP BY STOCK_LOCATIONS.sku
HAVING COUNT(STOCK_LOCATIONS.sku) > 1
) AS RowCount
FROM ORDER_DATA
INNER JOIN STOCK_DATA
ON ORDER_DATA.STOCK = STOCK_DATA.STOCK_CODE
INNER JOIN STOCK_LOCATIONS
ON ORDER_DATA.STOCK = STOCK_LOCATIONS.sku
INNER JOIN LOCATION_DATA
ON STOCK_LOCATIONS.location = LOCATION_DATA.location
WHERE ORDER_DATA.ORDER_REF = '21254'
GROUP BY ORDER_DATA.STOCK
ORDER BY LOCATION_DATA.pick_order ASC
这里有一些样本数据
和所需产出的例子
STOCK_LOCATIONS
sku location
123456 A1
123457 A2
123459 C1
123456 B1
123457 B2
LOCATION_DATA
location pick
A1 Y
A2 Y
B1 N
B2 N
C1 N
STOCK_DATA
STOCK_CODE PHYSICAL
123456 10
123457 0
123459 100
ORDER_DATA
ENTRY STOCK ORDER_QTY
1 123456 10
2 123457 2
3 123459 1
RETURN DATA
STOCK_CODE ENTRY LOCATION PICK ORDER_QTY PHYSICAL
123456 1 A1 Y 10 10
123457 2 A2 Y 2 0
123459 3 C1 N 1 100
这里有一个更新的尝试,因为它会导致与未知表格有关的错误:
// OPTION 1
SELECT
STOCK_LOCATIONS.*,
LOCATION_DATA.*,
STOCK_DATA.PHYSICAL,
ORDER_DATA.ENTRY,
ORDER_DATA.STOCK,
ORDER_DATA.ORDER_QTY,
(SELECT
COUNT(STOCK_LOCATIONS.location)
FROM STOCK_LOCATIONS
WHERE ORDER_DATA.STOCK = STOCK_LOCATIONS.sku
GROUP BY STOCK_LOCATIONS.sku
HAVING COUNT(STOCK_LOCATIONS.sku) > 1
) AS RowCount,
(SELECT
CASE
WHEN dat1.pick IS NOT NULL THEN loc1.location
ELSE loc2.location
END
) AS location
FROM ORDER_DATA
INNER JOIN STOCK_DATA
ON ORDER_DATA.STOCK = STOCK_DATA.STOCK_CODE
LEFT JOIN STOCK_LOCATIONS loc1
ON ORDER_DATA.STOCK = loc1.sku
LEFT JOIN LOCATION_DATA dat1
ON loc1.location = dat1.location
AND dat1.pick = 'Y'
LEFT JOIN STOCK_LOCATIONS loc2
ON ORDER_DATA.STOCK = loc2.sku
LEFT JOIN STOCK_LOCATIONS dat2
ON loc2.location = dat2.location
AND dat1.pick = 'N'
WHERE ORDER_DATA.ORDER_REF = '".$_GET_q."'
GROUP BY ORDER_DATA.STOCK
ORDER BY LOCATION_DATA.pick_order ASC
// OPTION 2
SELECT
STOCK_LOCATIONS.*,
LOCATION_DATA.*,
STOCK_DATA.PHYSICAL,
ORDER_DATA.ENTRY,
ORDER_DATA.STOCK,
ORDER_DATA.ORDER_QTY,
(SELECT
COUNT(STOCK_LOCATIONS.location)
FROM STOCK_LOCATIONS
WHERE ORDER_DATA.STOCK = STOCK_LOCATIONS.sku
GROUP BY STOCK_LOCATIONS.sku
HAVING COUNT(STOCK_LOCATIONS.sku) > 1
) AS RowCount
FROM ORDER_DATA
INNER JOIN STOCK_DATA
ON ORDER_DATA.STOCK = STOCK_DATA.STOCK_CODE
JOIN STOCK_LOCATIONS loc1
ON ORDER_DATA.STOCK = loc1.sku
JOIN LOCATION_DATA dat1
ON loc1.location = dat1.location
AND dat1.pick = CASE WHEN EXISTS
(SELECT
*
FROM STOCK_LOCATIONS loc2
JOIN LOCATION_DATA dat2
ON loc2.location = dat2.location
AND dat1.pick = 'Y'
WHERE ORDER_DATA.STOCK = loc2.sku
)
THEN 'Y' ELSE 'N' END
WHERE ORDER_DATA.ORDER_REF = '".$_GET_q."'
GROUP BY ORDER_DATA.STOCK
ORDER BY LOCATION_DATA.pick_order ASC
// OPTION 3
SELECT
STOCK_LOCATIONS.*,
LOCATION_DATA.*,
STOCK_DATA.PHYSICAL,
ORDER_DATA.ENTRY,
ORDER_DATA.STOCK,
ORDER_DATA.ORDER_QTY,
(SELECT
COUNT(STOCK_LOCATIONS.location)
FROM STOCK_LOCATIONS
WHERE ORDER_DATA.STOCK = STOCK_LOCATIONS.sku
GROUP BY STOCK_LOCATIONS.sku
HAVING COUNT(STOCK_LOCATIONS.sku) > 1
) AS RowCount,
(SELECT
STOCK_LOCATIONS.location
FROM STOCK_LOCATIONS
INNER JOIN LOCATION_DATA
ON STOCK_LOCATIONS.location = LOCATION_DATA.location
WHERE ORDER_DATA.STOCK = STOCK_LOCATIONS.sku
ORDER BY pick DESC, rand()
LIMIT 1
) AS location
FROM ORDER_DATA
INNER JOIN STOCK_DATA
ON ORDER_DATA.STOCK = STOCK_DATA.STOCK_CODE
INNER JOIN STOCK_LOCATIONS
ON ORDER_DATA.STOCK = STOCK_LOCATIONS.sku
INNER JOIN LOCATION_DATA
ON STOCK_LOCATIONS.location = LOCATION_DATA.location
WHERE ORDER_DATA.ORDER_REF = '".$_GET_q."'
GROUP BY ORDER_DATA.STOCK
ORDER BY LOCATION_DATA.pick_order ASC
答案 0 :(得分:0)
您可以加入位置表两次,一次是针对pick = 'Y'
的行,一次是针对pick = 'N'
的行。然后你可以使用case语句来优先考虑第一个,但是回到第二个:
SELECT case
when dat1.pick is not null then loc1.location
else loc2.location
end as Location
....
LEFT JOIN
STOCK_LOCATIONS loc1
ON ORDER_DATA.STOCK = loc1.sku
LEFT JOIN
LOCATION_DATA dat1
ON loc1.location = dat1.location
AND dat1.pick = 'Y'
LEFT JOIN
STOCK_LOCATIONS loc2
ON ORDER_DATA.STOCK = loc2.sku
LEFT JOIN
LOCATION_DATA dat2
ON loc2.location = dat2.location
AND dat1.pick = 'N'
另一个选项是带子查询的连接条件。子查询可以查找存在pick = 'Y'
的位置,否则返回pick = 'N'
。
JOIN STOCK_LOCATIONS loc1
ON ORDER_DATA.STOCK = loc1.sku
JOIN LOCATION_DATA dat1
ON loc1.location = dat1.location
AND dat1.pick = case when exists
(
select *
from STOCK_LOCATIONS loc2
JOIN LOCATION_DATA dat2
ON loc2.location = dat2.location
AND dat1.pick = 'Y'
WHERE ORDER_DATA.STOCK = loc2.sku
)
then 'Y' else 'N' end
答案 1 :(得分:0)
我认为您可以在select子句中将其作为子查询执行:
SELECT STOCK_LOCATIONS.*, LOCATION_DATA.*, STOCK_DATA.PHYSICAL,
ORDER_DATA.ENTRY, ORDER_DATA.STOCK, ORDER_DATA.ORDER_QTY,
(SELECT COUNT(STOCK_LOCATIONS.location)
FROM STOCK_LOCATIONS
WHERE ORDER_DATA.STOCK = STOCK_LOCATIONS.sku
GROUP BY STOCK_LOCATIONS.sku
HAVING COUNT(STOCK_LOCATIONS.sku) > 1
) AS RowCount,
(SELECT STOCK_LOCATIONS.location
FROM STOCK_LOCATIONS
WHERE ORDER_DATA.STOCK = STOCK_LOCATIONS.sku
order by pick desc, rand()
limit 1
) AS ChosenLocation
这会选择一行的相关子查询。它命令它们适合您想要的业务逻辑。如果您想了解有关该位置的更多信息,我会将其放入子查询中并加入其他信息。