Question

在Django管理员中，我想根据用户只显示模型的某些行。

class Article(models.Model):
    text =          models.TextField(max_length=160)
    location =        models.CharField(max_length=20)

因此，当用户登录管理网站并且是旧金山location的一部分时，他们应该只能看到Articles该位置。

Answer 1

我认为你想要的是ModelAdmin的查询集：

https://docs.djangoproject.com/en/1.4/ref/contrib/admin/#django.contrib.admin.ModelAdmin.queryset

class ArticleAdmin(admin.ModelAdmin):
    def queryset(self, request):
        qs = super(ArticleAdmin, self).queryset(request)
        if request.user.profile.location: # If the user has a location
            # change the queryset for this modeladmin
            qs = qs.filter(location=request.user.profile.location)
        return qs

这假设用户通过配置文件模型绑定到某个位置。

Answer 2

使用has_add_permission，has_change_permission和has_delete_permission与custom ModelAdmin（admin.py中）：

class ArticleAdmin(admin.ModelAdmin):
    def has_add_permission(self, request):
        # Nothing really to do here, but shown just to be thorough
        return super(ArticleAdmin, self).has_add_permission(request)

    def has_change_permission(self, request, obj=None):
        if obj is not None:
            return obj.location == request.user.get_profile().location
        else:
            return super(ArticleAdmin, self).has_change_permission(request, obj=obj)

    def has_delete_permission(self, request, obj=None):
        if obj is not None:
            return obj.location == request.user.get_profile().location
        else:
            return super(ArticleAdmin, self).has_delete_permission(request, obj=obj)
admin.site.register(Article, ArticleAdmin)

Django管理员根据权限过滤行

2 个答案: