我正在使用String split方法,我希望拥有最后一个元素。 数组的大小可以改变。
示例:
String one = "Düsseldorf - Zentrum - Günnewig Uebachs"
String two = "Düsseldorf - Madison"
我想拆分上面的字符串并获取最后一项:
lastone = one.split("-")[here the last item] // <- how?
lasttwo = two.split("-")[here the last item] // <- how?
我不知道运行时数组的大小:(
答案 0 :(得分:214)
或者你可以在String
上使用lastIndexOf()
方法
String last = string.substring(string.lastIndexOf('-') + 1);
答案 1 :(得分:153)
将数组保存在局部变量中,并使用数组的length
字段查找其长度。减去一个以说明它是基于0的:
String[] bits = one.split("-");
String lastOne = bits[bits.length-1];
答案 2 :(得分:21)
使用一个简单但通用的辅助方法,如下所示:
public static <T> T last(T[] array) {
return array[array.length - 1];
}
你可以改写:
lastone = one.split("-")[..];
为:
lastone = last(one.split("-"));
答案 3 :(得分:20)
您可以在Apache Commons中使用StringUtils类:
StringUtils.substringAfterLast(one, "-");
答案 4 :(得分:9)
String str = "www.anywebsite.com/folder/subfolder/directory";
int index = str.lastIndexOf('/');
String lastString = str.substring(index +1);
现在lastString
的值为"directory"
答案 5 :(得分:7)
聚集所有可能的方式!!
使用lastIndexOf()
&amp; Java.lang.String
substring()
种方法
// int firstIndex = str.indexOf( separator );
int lastIndexOf = str.lastIndexOf( separator );
String begningPortion = str.substring( 0, lastIndexOf );
String endPortion = str.substring( lastIndexOf + 1 );
System.out.println("First Portion : " + begningPortion );
System.out.println("Last Portion : " + endPortion );
split()
Java SE 1.4 。将提供的文本拆分为数组。
String[] split = str.split( Pattern.quote( separator ) );
String lastOne = split[split.length-1];
System.out.println("Split Array : "+ lastOne);
来自数组的Java 8顺序排序stream。
String firstItem = Stream.of( split )
.reduce( (first,last) -> first ).get();
String lastItem = Stream.of( split )
.reduce( (first,last) -> last ).get();
System.out.println("First Item : "+ firstItem);
System.out.println("Last Item : "+ lastItem);
Apache Commons Lang jar «org.apache.commons.lang3.StringUtils
String afterLast = StringUtils.substringAfterLast(str, separator);
System.out.println("StringUtils AfterLast : "+ afterLast);
String beforeLast = StringUtils.substringBeforeLast(str, separator);
System.out.println("StringUtils BeforeLast : "+ beforeLast);
String open = "[", close = "]";
String[] groups = StringUtils.substringsBetween("Yash[777]Sam[7]", open, close);
System.out.println("String that is nested in between two Strings "+ groups[0]);
Guava
:适用于Java的Google核心库。 «com.google.common.base.Splitter
Splitter splitter = Splitter.on( separator ).trimResults();
Iterable<String> iterable = splitter.split( str );
String first_Iterable = Iterables.getFirst(iterable, "");
String last_Iterable = Iterables.getLast( iterable );
System.out.println(" Guava FirstElement : "+ first_Iterable);
System.out.println(" Guava LastElement : "+ last_Iterable);
Scripting for the Java Platform«使用Rhino / Nashorn在JVM上运行Javascript
Rhino«Rhino是一个完全用Java编写的JavaScript的开源实现。它通常嵌入到Java应用程序中,以便为最终用户提供脚本。它作为默认的Java脚本引擎嵌入在J2SE 6中。
Nashorn是Oracle使用Java编程语言开发的JavaScript引擎。它基于Da Vinci Machine并已与Java 8一起发布。
Java Scripting Programmer's Guide
public class SplitOperations {
public static void main(String[] args) {
String str = "my.file.png.jpeg", separator = ".";
javascript_Split(str, separator);
}
public static void javascript_Split( String str, String separator ) {
ScriptEngineManager manager = new ScriptEngineManager();
ScriptEngine engine = manager.getEngineByName("JavaScript");
// Script Variables « expose java objects as variable to script.
engine.put("strJS", str);
// JavaScript code from file
File file = new File("E:/StringSplit.js");
// expose File object as variable to script
engine.put("file", file);
try {
engine.eval("print('Script Variables « expose java objects as variable to script.', strJS)");
// javax.script.Invocable is an optional interface.
Invocable inv = (Invocable) engine;
// JavaScript code in a String
String functions = "function functionName( functionParam ) { print('Hello, ' + functionParam); }";
engine.eval(functions);
// invoke the global function named "functionName"
inv.invokeFunction("functionName", "function Param value!!" );
// evaluate a script string. The script accesses "file" variable and calls method on it
engine.eval("print(file.getAbsolutePath())");
// evaluate JavaScript code from given file - specified by first argument
engine.eval( new java.io.FileReader( file ) );
String[] typedArray = (String[]) inv.invokeFunction("splitasJavaArray", str );
System.out.println("File : Function returns an array : "+ typedArray[1] );
ScriptObjectMirror scriptObject = (ScriptObjectMirror) inv.invokeFunction("splitasJavaScriptArray", str, separator );
System.out.println("File : Function return script obj : "+ convert( scriptObject ) );
Object eval = engine.eval("(function() {return ['a', 'b'];})()");
Object result = convert(eval);
System.out.println("Result: {}"+ result);
// JavaScript code in a String. This code defines a script object 'obj' with one method called 'hello'.
String objectFunction = "var obj = new Object(); obj.hello = function(name) { print('Hello, ' + name); }";
engine.eval(objectFunction);
// get script object on which we want to call the method
Object object = engine.get("obj");
inv.invokeMethod(object, "hello", "Yash !!" );
Object fileObjectFunction = engine.get("objfile");
inv.invokeMethod(fileObjectFunction, "hello", "Yashwanth !!" );
} catch (ScriptException e) {
e.printStackTrace();
} catch (NoSuchMethodException e) {
e.printStackTrace();
} catch (FileNotFoundException e) {
e.printStackTrace();
}
}
public static Object convert(final Object obj) {
System.out.println("\tJAVASCRIPT OBJECT: {}"+ obj.getClass());
if (obj instanceof Bindings) {
try {
final Class<?> cls = Class.forName("jdk.nashorn.api.scripting.ScriptObjectMirror");
System.out.println("\tNashorn detected");
if (cls.isAssignableFrom(obj.getClass())) {
final Method isArray = cls.getMethod("isArray");
final Object result = isArray.invoke(obj);
if (result != null && result.equals(true)) {
final Method values = cls.getMethod("values");
final Object vals = values.invoke(obj);
System.err.println( vals );
if (vals instanceof Collection<?>) {
final Collection<?> coll = (Collection<?>) vals;
Object[] array = coll.toArray(new Object[0]);
return array;
}
}
}
} catch (ClassNotFoundException | NoSuchMethodException | SecurityException
| IllegalAccessException | IllegalArgumentException | InvocationTargetException e) {
}
}
if (obj instanceof List<?>) {
final List<?> list = (List<?>) obj;
Object[] array = list.toArray(new Object[0]);
return array;
}
return obj;
}
}
JavaScript文件«StringSplit.js
// var str = 'angular.1.5.6.js', separator = ".";
function splitasJavaArray( str ) {
var result = str.replace(/\.([^.]+)$/, ':$1').split(':');
print('Regex Split : ', result);
var JavaArray = Java.to(result, "java.lang.String[]");
return JavaArray;
// return result;
}
function splitasJavaScriptArray( str, separator) {
var arr = str.split( separator ); // Split the string using dot as separator
var lastVal = arr.pop(); // remove from the end
var firstVal = arr.shift(); // remove from the front
var middleVal = arr.join( separator ); // Re-join the remaining substrings
var mainArr = new Array();
mainArr.push( firstVal ); // add to the end
mainArr.push( middleVal );
mainArr.push( lastVal );
return mainArr;
}
var objfile = new Object();
objfile.hello = function(name) { print('File : Hello, ' + name); }
答案 6 :(得分:6)
使用Guava:
final Splitter splitter = Splitter.on("-").trimResults();
assertEquals("Günnewig Uebachs", Iterables.getLast(splitter.split(one)));
assertEquals("Madison", Iterables.getLast(splitter.split(two)));
答案 7 :(得分:5)
因为他要求使用拆分在同一行中完成所有操作,所以我建议:
lastone = one.split("-")[(one.split("-")).length -1]
我总是尽量避免定义新的变量,我发现这是一个非常好的做法
答案 8 :(得分:3)
你的意思是你在编译时不知道数组的大小?在运行时,可以通过lastone.length
和lastwo.length
的值找到它们。
答案 9 :(得分:2)
在java 8中
String lastItem = Stream.of(str.split("-")).reduce((first,last)->last).get();
答案 10 :(得分:0)
我想你想在i行做这个。这有可能(虽然有点杂乱= ^)
new StringBuilder(new StringBuilder("Düsseldorf - Zentrum - Günnewig Uebachs").reverse().toString().split(" - ")[0]).reverse()
tadaa,一行 - &gt;你想要的结果(如果你拆分“ - ”(空间减去空间)而不是只有“ - ”(减号)你将在分区之前松开恼人的空间= ^)所以“GünnewigUebachs”而不是“GünnewigUebachs” (以空格作为第一个字符)
好的额外 - &gt; lib文件夹中不需要额外的JAR文件,因此您可以保持应用程序的轻量化。
答案 11 :(得分:0)
您也可以使用java.util.ArrayDeque
String last = new ArrayDeque<>(Arrays.asList("1-2".split("-"))).getLast();