Question

[WebInvoke(Method="POST",UriTemplate="/Users",RequestFormat=WebMessageFormat.Json)]
public string StudentUsers(Student user)
{
    return string.Format("Hello {0}", user.Name);
}

上面的代码是我的REST服务。我的客户代码是：

HttpWebRequest request = (HttpWebRequest)WebRequest.Create(url);
request.Method = "POST";
request.ContentType = "application/json; charset=utf-8";
Student user = 
    new Stuent {
        Name="Test User", 
        Email = "test@test.com",    
        Password = "test" 
    };                
DataContractJsonSerializer ser = new DataContractJsonSerializer(user.GetType());
MemoryStream ms = new MemoryStream();
ser.WriteObject(ms, user);
String json = Encoding.UTF8.GetString(ms.ToArray());
StreamWriter writer = new StreamWriter(request.GetRequestStream());
writer.Write(json);
writer.Close();

var httpResponse = (HttpWebResponse)request.GetResponse();
using (var streamReader = new StreamReader(httpResponse.GetResponseStream()))
{
    var result = streamReader.ReadToEnd();
    Console.WriteLine(result);
}

我的服务已托管，我正在使用webHttpBinding。当我调试我的REST服务时，我在Student对象中接收null。我确信我的post方法是在我通过在REST服务中将Name，Email和Password作为参数进行测试时发送数据，因此我的数据已成功发布但是我发布的Json数据未转换为Student对象。我在某处读到RESTfull服务会将该Json数据转换为对象。是真的还是我们需要明确转换它？

Answer 1

您需要为POST-ed数据发送Content-Length：

request.ContentLength = ms.Length;

有关详细信息，请参阅here：

Answer 2

我已通过将WebInvoke更改为

来解决此问题


    [WebInvoke(Method="POST",UriTemplate="/Users",RequestFormat=WebMessageFormat.Json,BodyStyle = WebMessageBodyStyle.Bare)]

RESTful Service不接受对象作为参数

2 个答案: