Question

我有这个jQuery菜单脚本：

<script type="text/javascript">
        jQuery(document).ready(function(){


            jQuery('#promo').pieMenu({icon : [
                    { 
                        path : "/wp-content/themes/Tersus/images/piemenu/winamp.png",
                        alt  : "Winamp",
                        fn   : function(){alert('Click:: Find');return false}
                    },  { 
                        path : "/wp-content/themes/Tersus/images/piemenu/vlc.png",
                        alt  : "VLC Media Player",
                        fn   : function(){alert('Click:: Plus');return false}   
                    },{ 
                        path : "/wp-content/themes/Tersus/images/piemenu/QuickTime.png",
                        alt  : "Quick Time Player",
                        fn   : function(){alert('Click:: Home');return false}
                    },{ 
                        path : "/wp-content/themes/Tersus/images/piemenu/WMP.png",
                        alt  : "Windows Media Player",
                        fn   : function(){alert('Click:: Music');return false}
                    },{ 
                        path : "/wp-content/themes/Tersus/images/piemenu/popup.png",
                        alt  : "נגן Popup",
                        fn   : function(){alert('Click: E-Mail');return false}
                    },{ 
                        path : "/wp-content/themes/Tersus/images/piemenu/iTunes.png",
                        alt  : "iTunes",
                        fn   : function(){alert('Click: Config');return false}

            });
        })
    </script>
                        },{

我需要在点击时将图标链接到外部URL，我该如何实现？

我正在写这行，因为它需要更好的代码解释，因为代码很长......（？）

Answer 1

function(){       
   window.location.href = 'http://domain.com/'; 
   return false
}

将jQuery菜单按钮链接到url

1 个答案: