在Dropzonejs中,我创建了删除按钮,然后将其附加到缩略图,如何使用addRemoveLinks:true
直接将我从服务器进行geeting的网址链接到删除按钮,
//Write function if you need to add some event after files added
myDropzone.on("addedfile", function(file) {
console.log('Files Added using ---------->'+$attrs.apiCall);
var _this=this;
/* Maybe display some more file information on your page */
var removeButton = Dropzone.createElement("<button data-dz-remove>-Remove file</button>");
removeButton.addEventListener("click", function(e) {
e.preventDefault();
e.stopPropagation();
_this.removeFile(file);
});
file.previewElement.appendChild(removeButton);
});
答案 0 :(得分:5)
您可以添加删除链接..在添加的文件事件中,您可以在服务器响应中获取URL并将其设置为删除链接。
myDropzone.on("addedfile", function (file) {
var _this = this;
/* Maybe display some more file information on your page */
var removeButton = Dropzone.createElement("<button data-dz-remove " +
"class='del_thumbnail btn btn-default'><span class='glyphicon glyphicon-trash'></span></button>");
removeButton.addEventListener("click", function (e) {
e.preventDefault();
e.stopPropagation();
var server_file = $(file.previewTemplate).children('.server_file').text();
// Do a post request and pass this path and use server-side language to delete the file
// $.post(server_file,{'X-CSRFToken': $cookies.csrftoken}, 'json');
$http({
method: 'POSt',
url: server_file,
headers: {
'X-CSRFToken': $cookies.csrftoken
}
});
_this.removeFile(file);
});
file.previewElement.appendChild(removeButton);
});
答案 1 :(得分:5)
这适用于Dropzone 5.0.0
<script>
Dropzone.options.dropzoneForm = {
addRemoveLinks: true,
dictDefaultMessage: "<strong>Drop files here or click to upload. </strong>",
init: function() {
this.on("complete", function(file) {
$(".dz-remove").html("<div><span class='fa fa-trash text-danger' style='font-size: 1.5em'></span></div>");
});
}
};
</script>
答案 2 :(得分:1)
添加
addRemoveLinks: true,
然后在
中使用以下内容init: function () {}
点击dz-remove后,它会转到它的父级,然后查找图片ID所在的span元素的文本。
使用$ ajax将imageId发送到您的操作并执行您想要的操作。 注意:我在这里使用toastr进行用户通知。
$(".dz-remove").on("click", function (e) {
e.preventDefault();
e.stopPropagation();
var imageId = $(this).parent().find(".dz-filename > span").text();
$.ajax({
url: "Your url here",
data: { imageId: imageId},
type: 'POST',
success: function (data) {
if (data.NotificationType === "Error") {
toastr.error(data.Message);
} else {
toastr.success(data.Message);
}},
error: function (data) {
toastr.error(data.Message);
}
})
});
希望这可以帮助你兄弟:)