Question

我是Ruby的新手，我正在尝试使用这种语言来实施摇滚剪刀锦标赛，作为练习。

在下面的代码中调用的rps_game_winner方法会在一对竞争对手中返回获胜者。

到目前为止，这是我的尝试：

def rps_tournament_winner(tournament)
  qualifying_round_winners = []
  for i in 0..0
  tournament.each_with_index do |x, xi|
    x.each_with_index do |y, yi|
      winner = rps_game_winner(y)
      qualifying_round_winners.push(winner) 
      qualifying_round_winners = qualifying_round_winners.each_slice(2).to_a
    end
  end
  tournament = qualifying_round_winners.each_slice(2).to_a
  end
  return tournament 
end

这是我提供的输入：

puts rps_tournament_winner([
 [
   [ ["Armando", "P"], ["David", "S"] ],
   [ ["Richard", "R"],  ["Michael", "S"] ]
 ]

])

我得到的输出是：

David
S
Richard
R

这是我被卡住的地方。我无法让这两个人相互竞争，并宣布最后的胜利者。

正如您在上面的代码中所看到的，for循环的终止条件需要引起注意。

有任何帮助吗？

Answer 1

我在您的代码中做了一些修改。

注意：如果我将[ ["Armando", "P"], ["David", "S"] ]作为rps_game_winner()功能的输入，则会提供["David", "S"]之类的结果。

def rps_tournament_winner(tournament)
  qualifying_round_winners = []
  for i in 0..0
  tournament.each_with_index do |x, xi|
    x.each_with_index do |y, yi|
      winner = rps_game_winner(y)
      qualifying_round_winners.push(winner) 
    end
  end
  tournament = rps_game_winner(qualifying_round_winners)
  end
  return tournament 
end

所以你的输入

[[ [["Armando", "P"], ["David", "S"]], [["Richard", "R"], ["Michael", "S"]] ]]

它还会返回["Richard", "R"]等结果。

在Ruby中实现Rock，Paper，Scissors比赛

1 个答案: