Question

我有一个字符串，如：

"aabbccccdd"

我想将此字符串分解为长度为2的子字符串向量：

"aa" "bb" "cc" "cc" "dd"

Answer 1

这是一种方式

substring("aabbccccdd", seq(1, 9, 2), seq(2, 10, 2))
#[1] "aa" "bb" "cc" "cc" "dd"

或更一般地

text <- "aabbccccdd"
substring(text, seq(1, nchar(text)-1, 2), seq(2, nchar(text), 2))
#[1] "aa" "bb" "cc" "cc" "dd"

编辑：这是更快，更快

sst <- strsplit(text, "")[[1]]
out <- paste0(sst[c(TRUE, FALSE)], sst[c(FALSE, TRUE)])

首先将字符串拆分为字符。然后，它将偶数元素和奇数元素粘贴在一起。

<强>计时

text <- paste(rep(paste0(letters, letters), 1000), collapse="")
g1 <- function(text) {
    substring(text, seq(1, nchar(text)-1, 2), seq(2, nchar(text), 2))
}
g2 <- function(text) {
    sst <- strsplit(text, "")[[1]]
    paste0(sst[c(TRUE, FALSE)], sst[c(FALSE, TRUE)])
}
identical(g1(text), g2(text))
#[1] TRUE
library(rbenchmark)
benchmark(g1=g1(text), g2=g2(text))
#  test replications elapsed relative user.self sys.self user.child sys.child
#1   g1          100  95.451 79.87531    95.438        0          0         0
#2   g2          100   1.195  1.00000     1.196        0          0         0

Answer 2

string <- "aabbccccdd"
# total length of string
num.chars <- nchar(string)

# the indices where each substr will start
starts <- seq(1,num.chars, by=2)

# chop it up
sapply(starts, function(ii) {
  substr(string, ii, ii+1)
})

哪个给出了

[1] "aa" "bb" "cc" "cc" "dd"

Answer 3

有两种简单的可能性：

s <- "aabbccccdd"

gregexpr 和 regmatches ：

regmatches(s, gregexpr(".{2}", s))[[1]]
# [1] "aa" "bb" "cc" "cc" "dd"

<强> strsplit ：

strsplit(s, "(?<=.{2})", perl = TRUE)[[1]]
# [1] "aa" "bb" "cc" "cc" "dd"

Answer 4

可以使用矩阵对字符进行分组：

s2 <- function(x) {
  m <- matrix(strsplit(x, '')[[1]], nrow=2)
  apply(m, 2, paste, collapse='')
}

s2('aabbccddeeff')
## [1] "aa" "bb" "cc" "dd" "ee" "ff"

不幸的是，这打破了奇数字符串长度的输入，发出警告：

s2('abc')
## [1] "ab" "ca"
## Warning message:
## In matrix(strsplit(x, "")[[1]], nrow = 2) :
##   data length [3] is not a sub-multiple or multiple of the number of rows [2]

更不幸的是，来自@GSee的g1和g2默默地为奇数字符串长度的输入返回错误的结果：

g1('abc')
## [1] "ab"

g2('abc')
## [1] "ab" "cb"

这是s2精神中的功能，为每组中的字符数取一个参数，并在必要时将最后一个条目留空：

s <- function(x, n) {
  sst <- strsplit(x, '')[[1]]
  m <- matrix('', nrow=n, ncol=(length(sst)+n-1)%/%n)
  m[seq_along(sst)] <- sst
  apply(m, 2, paste, collapse='')
}

s('hello world', 2)
## [1] "he" "ll" "o " "wo" "rl" "d" 
s('hello world', 3)
## [1] "hel" "lo " "wor" "ld"

（确实比g2慢，但比g1快了大约7倍）

Answer 5

丑陋但有效

sequenceString <- "ATGAATAAAG"

J=3#maximum sequence length in file
sequenceSmallVecStart <-
  substring(sequenceString, seq(1, nchar(sequenceString)-J+1, J), 
    seq(J,nchar(sequenceString), J))
sequenceSmallVecEnd <-
    substring(sequenceString, max(seq(J, nchar(sequenceString), J))+1)
sequenceSmallVec <-
    c(sequenceSmallVecStart,sequenceSmallVecEnd)
cat(sequenceSmallVec,sep = "\n")

给出 ATG AAT AAA ģ

如何将字符串拆分为给定长度的子字符串？

5 个答案: