Question

我有以下3个班级：

class Resource:
    id = Column(Integer, primary_key=True)
    path = Column(Text)
    data = Column(Binary)
    type = Column(Text)

    def set_resource(self, path, data, type):
        self.path = path
        self.data = data
        self.type = type

class EnvironmentResource(Base, Resource):
    __tablename__ = 'environment_resources'
    parent_id = Column(Integer, ForeignKey('environments.id', ondelete='CASCADE'))
    def __init__(self, path, data, type):
        self.set_resource(path, data, type)

class Environment(Base):
    __tablename__ = 'environments'
    id = Column(Integer, primary_key=True)
    identifier = Column(Text, unique=True)
    name = Column(Text)
    description = Column(Text)

    _resources = relationship("EnvironmentResource",
        cascade="all, delete-orphan",
        passive_deletes=True)
    _tools = relationship("Tool",
        cascade="all, delete-orphan",
        passive_deletes=True)

    def __init__(self, name, identifier, description):
        self.name = name
        self.identifier = identifier
        self.description = description

    def get_resource(self, path):
        return self._resources.filter(EnvironmentResource.path==path).first()

在调用get_resource时，我被告知'InstrumentedList'对象没有属性'filter' - 我已经阅读了文档并且无法解决这个问题。我缺少什么，以便我可以过滤与'get_resource'方法中的环境相对应的资源？

PS：我知道get_resource会抛出异常，这就是我希望它做的事情。

Answer 1

要使用与Query一样的relationship，您需要使用lazy='dynamic'对其进行配置。有关详情，请参阅Dynamic Relationship Loaders：

_resources = relationship("EnvironmentResource",
    cascade="all, delete-orphan",
    lazy='dynamic',
    passive_deletes=True)

sqlalchemy：'InstrumentedList'对象没有属性'filter'

1 个答案: