F#解决“逃离Zurg”难题

时间:2012-07-17 20:16:18

标签: f#

我写了一个F#程序来解决“Escape from Zurg”难题

我的代码如下。但是当解决谜题时,我返回布尔值的方式出了问题。

在线

retVal = Move (cost + (MoveCost toy1 toy2)) Right remainingElements

我收到警告

表达式应该具有'unit'类型,但类型为'bool'。如果指定属性,请使用语法'obj.Prop< - expr'

并且我看到即使该函数在谜题被推翻时该函数返回true。当它返回时,retVal仍为假。

以下是我的代码。

open System

type Direction = 
    | Left
    | Right

type Toy = {Name: string; Cost: int}

let toys = [
                {Name="Buzz"; Cost=5}; 
                {Name="Woody"; Cost=10}; 
                {Name="Rex"; Cost=20}; 
                {Name="Hamm"; Cost=25};
           ]

let MoveCost toy1 toy2 =
    if (toy1.Cost > toy2.Cost) then
        toy1.Cost
    else
        toy2.Cost

let rec Move cost direction group = 
    match group with
    | [] -> if (cost > 60) then
                false
            else 
                Console.WriteLine("Solution Found!")
                true
    | _ ->
        match direction with
        | Left ->
            let retVal = false
            let combinations = Set.ofSeq (seq {for i in group do for j in group do if i <> j then if i < j then yield i, j else yield j, i})
            for pair in combinations do
                let (toy1, toy2) = pair                
                let remainingElements = List.filter (fun t-> t.Name <> toy1.Name && t.Name <> toy2.Name) group                
                retVal = Move (cost + (MoveCost toy1 toy2)) Right remainingElements
                if (retVal) then
                    Console.WriteLine ("Move " + toy1.Name + " and " + toy2.Name + " with the total cost of " + cost.ToString())
            retVal
        | Right ->
            let retVal = false
            let toysOnRightBank = List.filter (fun t-> not(List.exists (fun g-> g = t) group)) toys
            for toy in toysOnRightBank do
                let cost = cost + toy.Cost
                let retVal = Move cost Left (toy :: group)
                if (retVal) then
                    Console.WriteLine("Move " + toy.Name + " back with the cost of " + toy.Cost.ToString())
            retVal

[<EntryPoint>]
let main args =
    let x = Move 0 Left toys
    0

1 个答案:

答案 0 :(得分:4)

您无法重新分配let绑定。它应该是:

let mutable retVal = false

...

retVal <- Move (cost + (MoveCost toy1 toy2)) Right remainingElements

但是,您可以轻松地重写它,以便不需要mutable

let res =
  [
    for i in group do 
      for j in group do 
        if i < j then yield i, j elif i > j then yield j, i
  ]
  |> List.filter (fun (toy1, toy2) ->
    let remainingElements = List.filter (fun t-> t.Name <> toy1.Name && t.Name <> toy2.Name) group                
    Move (cost + (MoveCost toy1 toy2)) Right remainingElements)

match res with
| [] -> false
| _ ->
  res |> List.iter (fun (toy1, toy2) ->
    Console.WriteLine ("Move " + toy1.Name + " and " + toy2.Name + " with the total cost of " + cost.ToString()))
  true

编辑:如果您需要参考实施,我发布了complete solution on gist