Question

好的，我说我有字符串“hello my name is donald”

现在，我要删除从“hello”到“is”的所有内容问题是，“my name”可以是任何内容，也可以是“his son”

基本上，简单地执行stringByReplacingOccurrencesOfString将无效。

（我确实有RegexLite）

我该怎么做？

Answer 1

如下所示，它可以帮助您

NSString *hello = @"his is name is isName";
NSRange rangeSpace = [hello rangeOfString:@" " 
                                  options:NSBackwardsSearch];
NSRange isRange = [hello rangeOfString:@"is" 
                               options:NSBackwardsSearch 
                                 range:NSMakeRange(0, rangeSpace.location)];

NSString *finalResult = [NSString stringWithFormat:@"%@ %@",[hello substringToIndex:[hello rangeOfString:@" "].location],[hello substringFromIndex:isRange.location]];
NSLog(@"finalResult----%@",finalResult);

Answer 2

以下NSString类别可能对您有所帮助。它对我有用，但不是由我创造的。感谢作者。

<强>的NSString + Whitespace.h

#import <Foundation/Foundation.h>

@interface NSString (Whitespace)

- (NSString *)stringByCompressingWhitespaceTo:(NSString *)seperator;

@end

<强>的NSString + Whitespace.m

＃

import "NSString+Whitespace.h"

@implementation NSString (Whitespace)
- (NSString *)stringByCompressingWhitespaceTo:(NSString *)seperator
{
    //NSArray *comps = [self componentsSeparatedByCharactersInSet:[NSCharacterSet whitespaceCharacterSet]];
    NSArray *comps = [self componentsSeparatedByCharactersInSet:[NSCharacterSet whitespaceAndNewlineCharacterSet]];

    NSMutableArray *nonemptyComps = [[NSMutableArray alloc] init];

    // only copy non-empty entries
    for (NSString *oneComp in comps)
    {
        if (![oneComp isEqualToString:@""])
        {
            [nonemptyComps addObject:oneComp];
        }

    }

    return [nonemptyComps componentsJoinedByString:seperator];  // already marked as autoreleased
}
@end

Answer 3

如果你总是知道你的字符串将以'你好我的名字'开头，那么这是17个字符，包括最后的空格，所以如果你

NSString * hello = "hello my name is Donald Trump";
NSString * finalNameOnly = [hello substringFromIndex:17];

如何从nsstring中删除子字符串？

3 个答案: