Question

我有一个格式为

的输入字符串

在这里，我应该首先根据逗号分隔符分隔字符串，这会给我一个单独的字符串，如

“Jerry Lane”（尖括号）jerry.lane@gmail.com（括号内关闭）

然后我需要在＆lt;＆gt;之间保存提取字符串括号，基本上是字符串“jerry.lane@gmail.com”。我使用以下代码，但它给了我以下错误：

由于未捕获的异常'NSRangeException'而终止应用程序，原因：' - [__ NSCFConstantString substringWithRange：]：范围或索引越界'

-(NSArray *)parseString:(NSString *)string
{
  if(string)
  {
    NSArray *myArray = [string componentsSeparatedByString:@","];
    for(NSMutableString *myString in myArray)
    {
        NSRange start,end;
        start = [myString rangeOfString:@"<"];
        end = [myString rangeOfString:@">"];
        if(start.location != NSNotFound && end.location != NSNotFound)
        {
            NSString *emailAddress = [myString substringWithRange:NSMakeRange(start.location,end.location)];
            NSString *name = [myString substringToIndex:start.location];

            NSDictionary *myDictionary = [[NSDictionary alloc] init];
            [myDictionary setValue:emailAddress forKey:@"Dhruvil Vyas"];
            [testArray addObject:myDictionary];

        }
    }
}

return testArray;

}

Answer 1

substring采用的参数是起始位置和长度

不是起始位置和结束位置。

More Info

Answer 2

borrrden的回答是正确的。这是另一种方法。

-(NSArray *)parseString:(NSString *)string
{
  if(string)
  {
    NSArray *myArray = [string componentsSeparatedByString:@","];
    for(NSMutableString *myString in myArray)
    {
        NSArray *tempNameArray = [myString componentsSeparatedByString:@"<"];
        NSString *email = [tempNameArray objectAtIndex:1];

        NSArray *tempMailArray = [email componentsSeparatedByString:@">"];

        NSString *emailAddress = [tempMailArray objectAtIndex:0];
        NSString *name = [tempNameArray objectAtIndex:0];

        NSDictionary *myDictionary = [[NSDictionary alloc] init];
        [myDictionary setValue:emailAddress forKey:@"Dhruvil Vyas"];
        [testArray addObject:myDictionary];
    }
  }

 return testArray;
}

无法从NSString中提取子字符串

2 个答案: