Question

我正试图集中这个板，这是代码，我尝试用％* s，但它没有成功。有什么想法吗？

board = [["1","2","2"],["8*1","2@3","5*6"],["9","5","8"],["2","2","2"],
     ["5*6","6*8","0@2"],["1","2","8"],["1","9","8"],["2*7","7*5","4@2"],["1","3","3"]]

counter = 0

print("--------------+---------------+-------------------")

for row in board:
    counter += 1
    print("|"      "%s"     "|") % ("       |      ".join(row).center(47))
    if counter == 3 or counter == 6 or counter == 9:
        print("---------------+---------------------+--------------")

每个方框的输出应该是这样的

        +-----------+
        | 1 | 1 | 9 |

        |2@3|1*6|7*2|

        | 4 | 1 | 2 |
        +-----------+

Answer 1

这就是你想要的，我相信：

board=[["1","2","2"],["8*1","2@3","5*6"],["9","5","8"],["2","2","2"],
["5*6","6*8","0@2"],["1","2","8"],["1","9","8"],["2*7","7*5","4@2"],["1","3","3"]]
counter=0

print ("----------------+---------------+----------------")

for row in board:
        counter+=1
        s="|"
        for column in row:
                s += column.center(15) + "|"
        print(s)
        if counter==3 or counter==6 or counter==9:
                print ("----------------+---------------+----------------")

输出：

----------------+---------------+----------------
|       1       |       2       |       2       |
|      8*1      |      2@3      |      5*6      |
|       9       |       5       |       8       |
----------------+---------------+----------------
|       2       |       2       |       2       |
|      5*6      |      6*8      |      0@2      |
|       1       |       2       |       8       |
----------------+---------------+----------------
|       1       |       9       |       8       |
|      2*7      |      7*5      |      4@2      |
|       1       |       3       |       3       |
----------------+---------------+----------------

Answer 2

("|"      "%s"     "|")

这是三个字符串文字："|"，"%s"和"|"，用空格分隔。 Python将在编译时将它们连接在一起，因为它们是文字（而不是碰巧包含字符串的变量;这种分析不能在编译时完成）。所以整个事情相当于“|％s |”。

如果希望空格包含在字符串中，则在字符串中包含空格：“|％s |”，每边需要任意数量的空格。或者，使用字符串乘法和加法运算来构造字符串："|" + " " * n + "%s" + " " * n + "|"，例如，其中n是每边需要的任意数量的空格。

Answer 3

我修改了你的代码以产生一些接近你要求的东西：

board = [["1","2","2"],["8*1","2@3","5*6"],["9","5","8"],
         ["2","2","2"],["5*6","6*8","0@2"],["1","2","8"],
         ["1","9","8"],["2*7","7*5","4@2"],["1","3","3"]]

counter = 0

print("+-----------+")

for row in board:
    counter += 1
    print("|%s|" % "|".join(c.center(3) for c in row))
    if counter == 3 or counter == 6 or counter == 9:
        print("+-----------+")

产生：

+-----------+
| 1 | 2 | 2 |
|8*1|2@3|5*6|
| 9 | 5 | 8 |
+-----------+
| 2 | 2 | 2 |
|5*6|6*8|0@2|
| 1 | 2 | 8 |
+-----------+
| 1 | 9 | 8 |
|2*7|7*5|4@2|
| 1 | 3 | 3 |
+-----------+

将矩阵居中

3 个答案: