我在python中有一个项目，我试图使用Python 2.7从IDLE运行当我运行程序时，文本文件确实按照我想要的方式创建，但是没有写入任何信息，我不明白为什么这种情况正在发生。我在Ubuntu 12.04 LTS笔记本电脑上按IDLE中的F5键将其作为模块运行。
以下是代码：
import time
import MySQLdb
import tweepy
from tweepy.streaming import StreamListener
from tweepy import OAuthHandler
from tweepy import Stream
# Go to http://dev.twitter.com and create an app.
# The consumer key and secret will be generated for you after
consumer_key=" # Omitted "
consumer_secret=" # Omitted "
# After the step above, you will be redirected to your app's page.
# Create an access token under the the "Your access token" section
access_token=" # Omitted "
access_token_secret=" # Omitted "
auth = tweepy.OAuthHandler(consumer_key, consumer_secret)
auth.set_access_token(access_token, access_token_secret)
api = tweepy.API(auth)
# If the authentication was successful, you should
# see the name of the account print out
print api.me().name
class StdOutListener(StreamListener):
""" A listener handles tweets are the received from the stream.
This is a basic listener that just prints received tweets to stdout.
"""
def on_data(self, data):
print data
return True
def on_error(self, status):
print status
if __name__ == '__main__':
l = StdOutListener()
stream = Stream(auth, l)
stream.filter(track=['#google'])
我在github上的文件，如果有人想在github上与我一起工作： stocktwitterdb.py
使用tweepy的流媒体示例可以在github上找到： tweepy streaming.py
现在我遇到了shell，我想把它们放到数据库或文本文件中。
答案 0 :(得分：3)
嗯，这看起来像是一个很好的例子，为什么做一个裸try/except是个坏主意。
首先，如果在打印过程中确实发生任何UnicodeDecodeError，则不会将任何内容写入您的文件，因为将跳过该部分代码。
其次，如果发生任何其他异常，你甚至都不会注意到它，因为你默默地捕捉（并忽略）所有这些异常。
所以至少要做
except UnicodeDecodeError:
print "Record skipped!"
并查看可能发生的其他（如果有）异常。
答案 1 :(得分：0)
import time
import MySQLdb
import tweepy
from textwrap import TextWrapper
from getpass import getpass
qParam = "Twitter"
def __init__(self, target):
super(StockTweetListener, self).__init__();
self.target = target
with open('results.txt', 'w') as f:
while True:
stream = tweepy.Stream(username, password, StockTweetListener(target), timeout=None);
stream.filter(None, stock_list)
target.truncate()
def debug_print(text):
"""Print text if debugging mode is on"""
if settings.debug:
print text
class StockTweetListener(tweepy.StreamListener):
status_wrapper = TextWrapper(width=60, initial_indent=' ', subsequent_indent=' ')
def on_status(self, status):
try:
# print 'Status : %s' %(self.status_wrapper.fill(status.text))
print '\nStatus : %s' %(status.text)
print '\nAuthor : %s' %(status.author.screen_name)
print '\nDate/Time : %s' %(status.created_at)
print '\nSource : %s' %(status.source)
print '\nGeo : %s' %(status.geo)
print '\n\n\n-----------------------------------------------------------------------------\n\n\n'
l1 = '\nStatus : %s' %(status.text)
l2 = '\nAuthor : %s' %(status.author.screen_name)
l3 = '\nDate/Time : %s' %(status.created_at)
l4 = '\nSource : %s' %(status.source)
l5 = '\nGeo : %s' %(status.geo)
l6 = '\n\n\n-----------------------------------------------------------------------------\n\n\n'
target.write(l1)
target.write(l2)
target.write(l3)
target.write(l4)
target.write(l5)
target.write(l6)
except UnicodeDecodeError:
# Catch any unicode errors while printing to console
# and just ignore them to avoid breaking application.
pass
def on_error(self, status_code):
print 'An error has occured! Status code = %s' % status_code
target.close()
return True # keep stream alive
def on_timeout(self):
print 'Snoozing Zzzzzz'
target.close()
def main():
username = raw_input('Twitter username: ')
password = getpass('Twitter password: ')
stock = raw_input('Name of Stocks(comma seperated): ')
stock_list = [u for u in stock.split(',')]
stream = tweepy.Stream(username, password, StockTweetListener(target), timeout=None)
# follow_list = None
stream.filter(None, stock_list)
if __name__ == '__main__':
try:
main()
except KeyboardInterrupt:
target.close()
quit()
这会产生错误
答案 2 :(得分：0)
你需要做出的改变有些混乱，所以我将在这里发布一个有希望修复的版本，以及关于为什么事情就是这样的一些评论。
import time
import MySQLdb # also not currently used
import tweepy
from textwrap import TextWrapper # not used currently
from getpass import getpass
# define the format for messages here to avoid repetition
OUT_STR = '''
Status : %(text)s
Author : %(author)s
Date/Time : %(date)s
Source : %(source)s
Geo : %(geo)s
-----------------------------------------------------------------------------
'''
class StockTweetListener(tweepy.StreamListener):
def __init__(self, target):
super(StockTweetListener, self).__init__();
self.target = target
# status_wrapper = TextWrapper(width=60, initial_indent=' ',
# subsequent_indent=' ')
# This isn't used in the current code. But, if you were going
# to use it, you'd need to assign it to self.status_wrapper;
# otherwise the variable would be local to this __init__ method
# and inaccessible from anything else.
def on_status(self, status):
try:
msg = OUT_STR % {
'text': status.text,
'author': status.author.screen_name,
'date': status.created_at,
'source': status.source,
'geo': status.geo,
}
print msg
self.target.write(msg)
# use self.target here. self is one of the paramaters to this
# method and refers to the object; because you assigned to its
# .target attribute before, you can use it here.
except UnicodeDecodeError:
# Catch any unicode errors while printing to console
# and just ignore them to avoid breaking application.
print "Record Skipped"
def on_error(self, status_code):
print 'An error has occured! Status code = %s' % status_code
return True # keep stream alive
def on_timeout(self):
print 'Snoozing Zzzzzz'
def main():
username = raw_input('Twitter username: ')
password = getpass('Twitter password: ')
stock = raw_input('Name of Stocks(comma seperated): ')
stock_list = [u for u in stock.split(',')]
follow_list = None # ??? you don't seem to define this variable
# open results.txt here and name it f locally. once code flow leaves
# the with statement, in this case only through an exception happening
# that jumps you out of the while loop, the file will be closed.
with open('results.txt', 'w') as f:
while True:
stream = tweepy.Stream(
username, password,
StockTweetListener(f), # passes the file to __init__
# as the "target" argument
timeout=None)
stream.filter(follow_list, stock_list)
if __name__ == '__main__':
try:
main()
except KeyboardInterrupt:
quit()