Question

使用MOXy我可以在我的json输出中展平我的对象模型的部分

即

<java-type name="Medium">
  <java-attributes>
    <xml-element java-attribute="trackList" xml-path="."/>
  </java-attributes>
</java-type>

但是当我想折叠一个静态类的子类时，如下所示

<java-type name="Medium.TrackList">
  <java-attributes>
    <xml-element java-attribute="artistList" xml-path="."/>
  </java-attributes>
</java-type>

抱怨

Exception Description: Could not load class [Medium.TrackList] declared in the external metadata file.  Please ensure that the class name is correct, and that the correct ClassLoader has been set.
    at org.eclipse.persistence.exceptions.JAXBException.couldNotLoadClassFromMetadata(JAXBException.java:376)
    at org.eclipse.persistence.jaxb.JAXBContext$TypeMappingInfoInput.getXmlBindingsClasses(JAXBContext.java:979)
    at org.eclipse.persistence.jaxb.JAXBContext$TypeMappingInfoInput.createContextState(JAXBContext.java:879)
    at org.eclipse.persistence.jaxb.JAXBContext.<init>(JAXBContext.java:157)

如何解决此问题？

Answer 1

在OXM中指定内部类时，EclipseLink实际上需要“$”分隔符。我复制了你的问题，并通过在你的oxm文件中更改它来修复它。

<java-type name="Medium$TrackList">
  <java-attributes>
    <xml-element java-attribute="artistList" xml-path="."/>
  </java-attributes>
</java-type>

希望这有帮助，

瑞克

如何获取MOXy xml映射文件以识别静态类

1 个答案: