使用五个观察值和两个因子变量来查看此测试数据集。
test
respid s2q1 s2q2
1 32 9 5 - V. satisfied
2 35 10 - Definitely 5 - V. satisfied
3 148 10 - Definitely 5 - V. satisfied
4 371 3 2
5 416 10 - Definitely 5 - V. satisfied
当我运行以下melt
命令时,我收到一个对我没有意义的错误。特别是因为我在成功之前使用了相同的命令。
require(reshape2)
qhist <- melt(test, id="respid")
Error in data.frame(ids, variable, value, stringsAsFactors = FALSE) :
arguments imply differing number of rows: 5, 10
数据是用
导入的spss.get("data.sav", lowernames=T, use.value.labels=T,max.value.labels=13)
dput(test)
structure(list(respid = structure(c(32L, 35L, 148L, 371L, 416L), label = structure("Serial Number", .Names = "respid"), class = "labelled"),
s2q1 = structure(c(10L, 11L, 11L, 4L, 11L), .Label = c("0 - Definitely not",
"1", "2", "3", "4", "5", "6", "7", "8", "9", "10 - Definitely",
"Don't know"), class = c("labelled", "factor"), label = structure("S2Q1 xxx?", .Names = "s2q1")),
s2q2 = structure(c(5L, 5L, 5L, 2L, 5L), .Label = c("1 - Not at all satisfied",
"2", "3", "4", "5 - V. satisfied", "Don't know"), class = c("labelled",
"factor"), label = structure("S2Q2 xxx?", .Names = "s2q2"))), .Names = c("respid",
"s2q1", "s2q2"), row.names = c(NA, 5L), class = "data.frame")
答案 0 :(得分:5)
它是由respid
的结构引起的,即因为它的类被“标记”了,但这有效:
library(reshape)
reshape::melt(test, id="respid")
respid variable value
1 32 s2q1 9
2 35 s2q1 10 - Definitely
3 148 s2q1 10 - Definitely
4 371 s2q1 3
5 416 s2q1 10 - Definitely
6 32 s2q2 5 - V. satisfied
7 35 s2q2 5 - V. satisfied
8 148 s2q2 5 - V. satisfied
9 371 s2q2 2
10 416 s2q2 5 - V. satisfied
或者如果不使用reshape
那么
class(test$respid) <- "factor"
reshape2::melt(test, id="respid")
也有效。