Objective-C,为什么这些NSArray不匹配?

时间:2012-07-10 01:44:44

标签: objective-c comparison nsarray

我有两个我正在比较的NSArrays - 在NSLog输出中它们看起来完全一样,但它们在某种程度上并不相同。如果我将NSArray转换为NSString,我会得到相同的结果。将它们与自己进行比较将是平等的。我怎样才能确定为什么一和二不相等?谢谢。

- (void)confused:(NSArray *)two {

    NSArray *one = [NSArray arrayWithObjects:@"16777223", @"7", nil];
    NSArray *two = [[NSBundle bundleWithPath:@"/path/to/bundle"] executableArchitectures];

    // NSArray "two" shows as 16277223, 7 in NSLog

    if ([two firstObjectCommonWithArray:(NSArray *)one])
    {
        NSLog(@"- it's equal %@ %@", one, two);
        // if array one matches array two then this will output
    }
    else {
        NSLog(@"- it's NOT equal %@ %@", one, two);
    }

    return;
}

这是控制台的输出:

myApp (
    16777223,
    7
)
myApp (
    16777223,
    7
)
myApp - it's NOT equal (
    16777223,
    7
)(
    16777223,
    7
)

1 个答案:

答案 0 :(得分:1)

-[NSBundle executableArchitectures]返回NSNumber个对象的数组,而不是NSString个对象,因此您传入的数组中没有字符串。如果你改变了

NSArray *one = [NSArray arrayWithObjects:@"16777223",@"7", nil];

NSArray *one = [NSArray arrayWithObjects:[NSNumber numberWithUnsignedInteger:NSBundleExecutableArchitectureX86_64], 
                                         [NSNumber numberWithUnsignedInteger:NSBundleExecutableArchitectureI386], 
                  nil];

您的代码应该有效。