Question

我有一个以这种格式保存字符串的文件：

ACHMU)][2:s,161,(ACH Payment Sys Menus - Online Services)][3:c,1,(M)][4:c,1,(N)]
ACLSICZ)][2:s,161,(Report for Auto Closure)][3:c,1,(U)][4:c,1,(N)]
ACMPS)][2:s,161,(Account Maintenance-Pre-shipment Account)][3:c,1,(U)][4:c,1,(N)]
ACNPAINT)][2:s,161,(Interest Run For NPA Accounts)][3:c,1,(U)][4:c,1,(N)]

我需要拆分字符串，以便我拥有以下格式的数据：

ACHMU (ACH Payment Sys Menus - Online Services)
ACLSICZ (Report for Auto Closure)......

基本上，我想删除“）[2：s，161，”部分和“] [3：c，1，（M）] [4：c，1，（N）]”结束。分裂字符串会帮助我吗？以下方法已失败：

FileInputStream fs = new FileInputStream(C:/Test.txt);
BufferedReader br  = new BufferedReader(new InputStreamReader(fs));
String str;
while((str = br.readLine()) != null){
    String[] split = str.Split(")[2:s,161,")
}

请帮我把垃圾放在中间和最后。

Answer 1

直截了当，使用substring()和indexOf()：

String oldString = "ACHMU)][2:s,161,(ACH Payment Sys Menus - Online Services)][3:c,1,(M)][4:c,1,(N)]";
String firstPart = oldString.substring(0, oldString.indexOf(")")); // ACHMU
String secondPart = oldString.substring(oldString.indexOf("(")); // (ACH Payment Sys Menus - Online Services)][3:c,1,(M)]
String newString = firstPart + " " + secondPart.substring(0, secondPart.indexOf(")") + 1); // ACHMU (ACH Payment Sys Menus - Online Services)
System.out.print(newString);

<强>输出：

ACHMU（ACH支付系统菜单 - 在线服务）

Answer 2

您可以使用

str.replaceFirst("(.*?)\\)\\].*?(\\(.*?\\))\\].*", "$1 $2");

Answer 3

FileInputStream fs = new FileInputStream(C:/Test.txt);
BufferedReader br  = new BufferedReader(new InputStreamReader(fs));
String str;
String newStr;
String completeNewStr="";
while((str = br.readLine()) != null)
{
    newStr = str.replace(")][2:s,161,"," ");
    newStr = str.replace("][3:c,1,(M)][4:c,1,(N)]","");
    completeNewStr+=newStr;
}

// completeNewStr is your final string

Answer 4

如果要替换的字符串始终为“[2：s，161”，则将其替换为空字符串或空格（如果可接受的话）。同样，对于其他字符串也是如此。

str.replace("[2:s,161,", '');

如何拆分字符串以删除某些部件

4 个答案: