Question

我正在尝试将一个字符串分成几部分，但无法解决它！

我的主要观点来自一个字符串

from celery import Celery as _Celery


class Celery(_Celery)

    def get_message_count(self, queue):
        '''
        Raises: amqp.exceptions.NotFound: if queue does not exist
        '''
        with self.connection_or_acquire() as conn:
            return conn.default_channel.queue_declare(
                queue=queue, passive=True).message_count


celery = Celery(app)
num_messages = celery.get_message_count('my-queue')

从"hello bye see you"

读取

我试过

"bye" to "you"

但是我被困在代码的其他部分，我真的想要一些帮助。对不起，如果我不是最好的解释事情，至少我尽力了：/

Answer 1

我假设您的预期输出为bye see you。如果我理解正确，那么可以使用方法来获得所需的输出：

在此字符串中拆分为带有分隔符splits()的数组（" "），并找到索引bye（j）和you（{{1然后在数组中使用k在for loop和bye之间的数组中获取字符串。

you

用法：

Function GETSTRINGBETWEEN(ByVal start As String, ByVal parent As String, ByVal [end] As String)
        Dim output As String = ""
        Dim splits() As String = parent.Split(" ")
        Dim i As Integer
        Dim j As Integer = Array.IndexOf(splits, start)
        Dim k As Integer = Array.IndexOf(splits, [end])
        For i = j To k
            If output = String.Empty Then
                output = splits(i)
            Else
                output = output & " " & splits(i)
            End If
        Next
        Return output
    End Function

Dim val As String
val = GETSTRINGBETWEEN("bye", "hello bye see you", "you")
'val="bye see you"

用法：

Function GET_STRING_BETWEEN(ByVal start As String, ByVal parent As String, ByVal [end] As String)
        Dim output As String
        output = parent.Substring(parent.IndexOf(start) _
                                                , (parent.IndexOf([end]) _
                                                   - parent.IndexOf(start)) _
                                                   ).Replace(start, "").Replace([end], "")
        output = start & output & [end]
        Return output
    End Function

将字符串拆分为多个部分

1 个答案: