Question

我的查询有问题。此查询适用于phpMyAdmin，但是当PHP执行此查询时出错。可能是什么原因？

我的PHP代码是：

var_dump($sql);
query($sql);

我调试时：

这是查询字符串：

 UPDATE searchcolumnsets SET name = "Project X",jsonfields = "[{\"name\":\"cm:contentPropertyName\",\"title\":\"Thumbnailed Content Property Name\",\"description\":\"\",\"datatype\":\"\"},{\"name\":\"cm:defaultHomeFolderPath\",\"title\":\"Percorso cartella homepage\",\"description\":\"\",\"datatype\":\"\"},{\"name\":\"trx:enabled\",\"title\":\"Abilitato\",\"description\":\"\",\"datatype\":\"\"},{\"name\":\"cm:identifier\",\"title\":\"Identificativo\",\"description\":\"\",\"datatype\":\"\"},{\"name\":\"cm:expiryDate\",\"title\":\"Data di scadenza\",\"description\":\"Data di scadenza\",\"datatype\":\"d:date\"},{\"name\":\"cm:hits\",\"title\":\"Conteggio\",\"description\":\"Conteggio\",\"datatype\":\"d:int\"}]" WHERE id = 50

这是错误：

您的SQL语法有错误;查看与您的MySQL服务器版本对应的手册，以便在'name'附近使用正确的语法：“cm：contentPropertyName”，“title”：“Thumbnailed Content Property Name”，“desc”在第1行

Answer 1

您可以使用单引号代替。试试这个

UPDATE searchcolumnsets SET name = 'Project X',jsonfields = '[{\"name\":\"cm:contentPropertyName\",\"title\":\"Thumbnailed Content Property Name\",\"description\":\"\",\"datatype\":\"\"},{\"name\":\"cm:defaultHomeFolderPath\",\"title\":\"Percorso cartella homepage\",\"description\":\"\",\"datatype\":\"\"},{\"name\":\"trx:enabled\",\"title\":\"Abilitato\",\"description\":\"\",\"datatype\":\"\"},{\"name\":\"cm:identifier\",\"title\":\"Identificativo\",\"description\":\"\",\"datatype\":\"\"},{\"name\":\"cm:expiryDate\",\"title\":\"Data di scadenza\",\"description\":\"Data di scadenza\",\"datatype\":\"d:date\"},{\"name\":\"cm:hits\",\"title\":\"Conteggio\",\"description\":\"Conteggio\",\"datatype\":\"d:int\"}]' WHERE id = 50

PHP：查询函数erron执行更新查询字符串

1 个答案: