Question

我在使用带有WHERE子句的UPDATE语句时遇到了困难

我使用以下代码尝试更新表中的记录WHERE squadnumber是squadnumber下拉列表中的值。

<img src="header.png" alt="Southside FC Header">
<h1>Player Statistics</h1> 

<?php

require("config.inc.php");

if (!empty($_POST)) {

    //initial query
    $query = "UPDATE playerstatistics SET squadnumber=':squadnumber', appearances=':appearances', subappearances=':subappearances', 
    goalsscored=':goalsscored', yellowcards=':yellowcards', redcards=':redcards' WHERE squadnumber=':squadnumber'";

    //Update query
    $query_params = array(
        ':squadnumber' => $_POST['squadnumber'],
        ':appearances' => $_POST['appearances'],
        ':subappearances' => $_POST['subappearances'],
        ':goalsscored' => $_POST['goalsscored'],
        ':yellowcards' => $_POST['yellowcards'],
        ':redcards' => $_POST['redcards']

    );


    try {
        $stmt   = $db->prepare($query);
        $result = $stmt->execute($query_params);
    }
    catch (PDOException $ex) {
        // For testing, you could use a die and message. 
        //die("Failed to run query: " . $ex->getMessage());

        //or just use this use this one:
        $response["success"] = 0;
        header('Location: http://localhost/webservice/errorCouldNotAddData.php');
        die(json_encode($response));
    }

    $response["success"] = 1;
    header('Location: http://localhost/webservice/managerhomepage.php');
    echo json_encode($response);

} else {


?>
<br /> 

<form action="addplayerstatistic.php" method="post">

Squad Number: <br />
<select name="squadnumber">
<option value="1">1</option>
<option value="2">2</option>
<option value="3">3</option>
<option value="4">4</option>
<option value="5">5</option>
<option value="6">6</option>
<option value="7">7</option>
<option value="8">8</option>
<option value="9">9</option>
<option value="10">10</option>
<option value="11">11</option>
<option value="12">12</option>
<option value="14">14</option>
<option value="15">15</option>
<option value="16">16</option>
<option value="17">17</option>
</select>
<br />

Number of appearances:<br /> 
<input type="number" name="appearances"/><br />

Number of appearances as a substitute:<br /> 
<input type="number" name="subappearances"/><br />

Number of Goals Scored:<br /> 
<input type="number" name="goalsscored"/><br />

Number of yellow cards:<br /> 
<input type="number" name="yellowcards"/><br />

Number of red cards:<br /> 
<input type="number" name="redcards"/><br />

<input type="submit" value="Add statistics" /> 
</form>

<a href="managerhomepage.php"><img src="backButton.png"></a>
<?php

}

?>

$ response [＆＃34; success＆＃34;]被设置为1，因为查询似乎已正确运行，但是当我检查数据库时没有任何更改。

我认为我的问题是围绕WHERE子句没有设置为下拉列表中的数字，因此没有更新行。

有什么想法吗？

由于

Answer 1

尝试更新您的查询

$query = "UPDATE playerstatistics SET squadnumber=:squadnumber, appearances=:appearances, subappearances=:subappearances, 
goalsscored=:goalsscored, yellowcards=:yellowcards, redcards=:redcards WHERE squadnumber=:squadnumber";

你不应该逃避你的参数--PDO会为你做这件事。

更新查询执行但不更新表

1 个答案: