我试图制作Simon game。
我在编程游戏的中途,但我遇到了问题。
我希望程序从队列中读取以前在游戏中所有的值,然后按正确的顺序转动它们的颜色(我选择将它们变为灰色,然后再将它们恢复正常)这就是我的问题。如果你看一下方法play()
,你会看到我在那里写的评论。我该怎么做?
这是我的代码:
import java.awt.Color;
import java.awt.Font;
import java.awt.Graphics;
import java.awt.event.ActionEvent;
import java.awt.event.ActionListener;
import java.awt.event.MouseEvent;
import java.awt.event.MouseListener;
import java.awt.geom.Arc2D;
import java.util.Date;
import javax.swing.JPanel;
import javax.swing.Timer;
import unit4.collectionsLib.Queue;
public class window extends JPanel implements MouseListener , ActionListener{
Queue <Integer>data = new Queue<Integer> ();
Queue <Integer>temp = new Queue<Integer> ();
int random;
Timer prestart;
int prestartcount;
Color [] colors = {Color.red,Color.blue,Color.yellow,Color.green};
public window (){
prestart = new Timer (1000,this);
int prestartcount=0;
prestart.start();
}
public void play (){
random = (int)(Math.random()*4);
data.insert(random);
int x=0;
Color temp=Color.black;
x = data.remove();
this.temp.insert(x);
temp = colors[x];
colors[x]=Color.gray;
// delay of one second here
colors[x]=temp;
}
public void paintComponent(Graphics g) {
super.paintComponent(g);
g.setColor(colors[0]);
g.fillArc(80, 150, 250, 250, 0, 360);
g.setColor(colors[1]);
g.fillArc(80, 150, 250, 250, 0, 270);
g.setColor(colors[2]);
g.fillArc(80, 150, 250, 250, 0, 180);
g.setColor(colors[3]);
g.fillArc(80, 150, 250, 250, 0, 90);
g.drawString(prestartcount+"", 0, 30);
repaint();
}
@Override
public void mouseClicked(MouseEvent arg0) {
arg0.getLocationOnScreen();
}
@Override
public void mouseEntered(MouseEvent arg0) {
}
@Override
public void mouseExited(MouseEvent arg0) {
}
@Override
public void mousePressed(MouseEvent arg0) {
}
@Override
public void mouseReleased(MouseEvent arg0) {
}
@Override
public void actionPerformed(ActionEvent act) {
if (act.getSource()==prestart){
if (prestartcount<3)
prestartcount++;
else{
prestart.stop();
play();
}
}
}
}
答案 0 :(得分:3)
使用单拍Swing Timer
来翻转颜色并调用repaint()
。有关详细信息,请参阅Using Timers in Swing Applications。
答案 1 :(得分:1)
colors[x]=Color.gray;
// delay of one second here
timer = new Timer(0, new ActionListener() {
@Override
public void actionPerformed(ActionEvent evt) {
colors[x]=temp;
repaint(); //repaint the gui, or you want see the effect
}
});
timer.setInitialDelay(1000); //wait one second
timer.setRepeats(false); //only once
timer.start();
您可能需要进行临时决赛,或将其存放在其他地方。
答案 2 :(得分:0)
尝试使用Thread.sleep()。
Causes the currently executing thread to sleep (temporarily cease execution) for the specified number of milliseconds. The thread does not lose ownership of any monitors.
答案 3 :(得分:0)
Thread.sleep(1000)
就是您所需要的。