所以我在openGL中有一个圆柱体,我创建的不是使用gluCylinder,而是使用分段的GL_QUAD_STRIP来给人一种圆形管的印象。我想得到一个纹理图像,一直包裹在圆柱体周围,但无法弄清楚如何;当谈到OpenGL中的纹理时,我仍然是一个新手,所以也许我不像我想的那样理解纹理。这是我绘制圆柱体并尝试对其进行纹理化的代码:
float x,z,angle; // Used to calculate cylinder wall
float height = 75.0f; // Height of the cylinder
float diameter = 10.0f; // Diameter of the cylinder, or more specifically,
float normal[3],corners[2][3]; // Storeage for vertex calculations
float numSides = 100.0f;
float step;
float sideLength;
float perimeter; // Not perimeter of ideal circular cylinder
// but actual perimeter of what is drawn
int whichSide; // Used to keep track of which side you are on during the loop
step = (GL_PI/numSides/2.0f); // Approximate the cylinder wall with
// some number of flat segments
sideLength =
2.0f*diameter*(float)sin(GL_PI/(2.0f*numSides)); // Calculate the length of each side
perimeter = numSides * sideLength;
printf("There are %f sides on the small cylinder\nthat are each %f units
long.\nThe dimensions of the texture must be\nclose to %f x %f\n\n\n", numSides,
sideLength, perimeter, height);
// Set material color for head of screw
glColor3f(1.0f, 1.0f, 1.0f);
// Assemble the wall as 100 quadrilaterals formed by
// placing adjoining Quads together
glFrontFace(GL_CCW);
glBegin(GL_QUAD_STRIP);
for(angle = (2.0f*GL_PI); angle > 0.0f; angle -= step)
{
// Calculate x and y position of the first vertex
x = diameter*(float)sin(angle);
z = diameter*(float)cos(angle);
// Get the coordinate for this point and extrude the
// length of the cylinder.
corners[0][0] = x;
corners[0][1] = -height/2.0f;
corners[0][2] = z;
corners[1][0] = x;
corners[1][1] = height/2.0f;
corners[1][2] = z;
// Instead of using real normal to actual flat section
// Use what the normal would be if the surface was really
// curved. Since the cylinder goes up the Y axis, the normal
// points from the Y axis out directly through each vertex.
// Therefore we can use the vertex as the normal, as long as
// we reduce it to unit length first and assume the y component
// to be zero
normal[0] = corners[1][0];
normal[1] = 0.0f;
normal[2] = corners[1][2];
//@@@@@#####*****TEXTURING DONE HERE *****#####@@@@@//
// Reduce to length of one and specify for this point
ReduceToUnit(normal);
glNormal3fv(normal);
glTexCoord2f(((float)whichSide)/numSides,0.0f);
glVertex3fv(corners[0]);
glTexCoord2f(((float)whichSide)/numSides,1.0f);
glVertex3fv(corners[1]);
whichSide++;
}
答案 0 :(得分:3)
如果您认为纹理映射过程是将一张纸包裹在圆柱体周围(因此圆柱的高度=纸张的高度和圆柱的周长=纸张的宽度),您需要做的就是生成将角度改变Y(或X)的texcoords(但是这将从0-1开始,而角度从0变为Pi)。另一个纹理坐标X(或Y)将为0和1,因此它映射到该轴上的完整范围。