Question

可能重复：
Get dates from a week number in T-SQL

如果我在SQL查询中有一个周数，如何获取日期值。

如果我通过26，那就应该给我06/24/2012。如果我通过27，我应该得到07/01/2012

任何帮助将不胜感激：）

SOTS

Answer 1

在SQL Server中

DECLARE @StartDate DATE, @WeekVal INT
SET @WeekVal = 26 -- Set the week number
SET @StartDate = DATEADD(YEAR, DATEDIFF(YEAR, 0, GETDATE()), 0) -- Start of current year

;WITH cte AS (
    SELECT @StartDate AS DateVal, DATEPART(wk, @StartDate) AS WeekVal, 1 AS RowVal
    UNION ALL
    SELECT DATEADD(d, 1, DateVal),  DATEPART(wk, DATEADD(d, 1, DateVal)), RowVal + 1 
    FROM cte WHERE RowVal < 365
)
SELECT MIN(DateVal) StartOfWeek
FROM cte
WHERE WeekVal = @WeekVal
OPTION (MAXRECURSION 365);

Answer 2

SELECT DATEADD(week, n, '11/25/2011');

以n为周数

Answer 3

如果这不起作用，请尝试使用WEEK()代替WEEKOFYEAR()。

CURDATE() - INTERVAL WEEKDAY(CURDATE()) DAY + INTERVAL (WEEKNO - WEEKOFYEAR(CURDATE())) WEEK

Answer 4

这将为您提供一周的开始和结束日期。 [对于SQL Server]

Declare @week integer set @week = 26
Declare @Year Integer Set @Year = year(getdate())
declare @date datetime

-- ------------------------------------
Set @date = DateAdd(day, 0, 
            DateAdd(month, 0, 
            DateAdd(Year, @Year-1900, 0)))

set @date = Dateadd(week, @week-1, @date)

select @date startweek, DATEADD (D, -1 * DatePart (DW, @date) + 7, @date) endweek

这是它的结果：

startweek               endweek
----------------------- -----------------------
2012-07-01 00:00:00.000 2012-07-07 00:00:00.000

(1 row(s) affected)

日期SQL中的周数的值

4 个答案: