Question

我的网址总是以数字结尾，例如：

  String url = "localhost:8080/myproject/reader/add/1/";
  String anotherurl = "localhost:8080/myproject/actor/take/154/";

我想提取最后两个斜杠之间的数字（“/").

有谁知道我怎么做到这一点？

Answer 1

您可以拆分字符串：

String[] items = url.split("/");
String number = items[items.length-1]; //last item before the last slash

Answer 2

使用正则表达式：

final Matcher m = Pattern.compile("/([^/]+)/$").matcher(url);
if (m.find()) System.out.println(m.group(1));

Answer 3

使用lastIndexOf，如下所示：

 String url = "localhost:8080/myproject/actor/take/154/";
 int start = url.lastIndexOf('/', url.length()-2);
 if (start != -1) {
     String s = url.substring(start+1, url.length()-1);
     int n = Integer.parseInt(s);
     System.out.println(n);
 }

这是基本的想法。您将不得不进行一些错误检查（例如，如果在URL的末尾找不到数字），但它将正常工作。

Answer 4

对于您指定的输入

String url = "localhost:8080/myproject/reader/add/1/";
String anotherurl = "localhost:8080/myproject/actor/take/154/";

添加一点错误处理来处理缺少的“/”，如

String url = "localhost:8080/myproject/reader/add/1"; 
String anotherurl = "localhost:8080/myproject/actor/take/154";

String number = "";
if(url.endsWith("/") {
  String[] urlComps = url.split("/");
  number = urlComps[urlComps.length-1]; //last item before the last slash
} else {
  number = url.substring(url.lastIndexOf("/")+1, url.length());
}

Answer 5

一线：

 String num = (num=url.substring(0, url.length() - 1)).substring(num.lastIndexOf('/')+1,num.length());

Java：切片字符串

5 个答案: