为什么这个JavaScript cookie不起作用?

时间:2012-06-25 08:39:37

标签: javascript jquery html css cookies

我知道这个代码用来工作,我必须在重新安排由其他代码组成的div元素时意外地改变了一些东西,因此它现在似乎不起作用。如果有人对此有所了解,我会深表感激。我需要“display:none;”在窗口div?对不起,我不记得。

<script type="text/javascript">
    $(document).ready(function() {
     // If the 'hide cookie is not set we show the message
      if (!readCookie('hide')) {
        $('#window').show();
      }
      // Add the event that closes the popup and sets the cookie that tells us to
      // not show it again until one day has passed.
      $('#close').click(function() {
        $('#window').hide();
        createCookie('hide', true, 1)
        return false;
      });
    });
    // ---
    // And some generic cookie logic
    // ---
    function createCookie(name,value,days) {
      if (days) {
        var date = new Date();
        date.setTime(date.getTime()+(days*24*60*60*1000));
        var expires = "; expires="+date.toGMTString();
      }
      else var expires = "";
      document.cookie = name+"="+value+expires+"; path=/";
    }
    function readCookie(name) {
      var nameEQ = name + "=";
      var ca = document.cookie.split(';');
      for(var i=0;i &amp;amp;amp;amp;amp;amp;amp;amp;lt; ca.length;i++) {
        var c = ca[i];
        while (c.charAt(0)==' ') c = c.substring(1,c.length);
        if (c.indexOf(nameEQ) == 0) return c.substring(nameEQ.length,c.length);
      }
      return null;
    }
    function eraseCookie(name) {
      createCookie(name,"",-1);
    }
    </script>

1 个答案:

答案 0 :(得分:0)

你的for循环条件有问题。

应该是

    for(var i=0;i<ca.length;i++)