我从一开始就在学习Hibernate。我从RoseIndia下载了hibernated演示。 为特定数据库设置hibernate.cfg.xml的配置。并运行下面的代码。指定在上面的表'contact'是自动创建的,但是在代码下面无法保存新记录。下面的代码有什么问题吗?
package roseindia.tutorial.hibernate;
import org.hibernate.Session;
import org.hibernate.SessionFactory;
import org.hibernate.cfg.Configuration;
/**
* @author Deepak Kumar
*
* http://www.roseindia.net
* Hibernate example to inset data into Contact table
*/
public class FirstExample {
public static void main(String[] args) {
Session session = null;
try{
// This step will read hibernate.cfg.xml and prepare hibernate for use
SessionFactory sessionFactory = new Configuration().configure().buildSessionFactory();
session =sessionFactory.openSession();
//Create new instance of Contact and set values in it by reading them from form object
System.out.println("Inserting Record");
Contact contact = new Contact();
//contact.setId(6);
contact.setFirstName("Deepak");
contact.setLastName("Kumar");
contact.setEmail("deepak_38@yahoo.com");
System.out.println("Before Save");
session.save(contact);
System.out.println("After Save");
System.out.println("Done");
}catch(Exception e){
System.out.println(e.getMessage());
}finally{
// Actual contact insertion will happen at this step
session.flush();
session.close();
}
}
}
我的输出如下
log4j:WARN No appenders could be found for logger (org.hibernate.cfg.Environment).
log4j:WARN Please initialize the log4j system properly.
Inserting Record
Before Save
After Save
Done
Hibernate: insert into CONTACT (FIRSTNAME, LASTNAME, EMAIL, ID) values (?, ?, ?, ?)
答案 0 :(得分:7)
您需要将代码包装在事务中:
session = sessionFactory.openSession();
Transaction transaction = session.beginTransaction();
// your code
transaction.commit();