Question

我目前正在为每个游戏创建2行数据，如下所示。然后我可以创建SQL代码来生成W，L，PF，PA和diff列，如图所示。有没有人知道如何通过输入一个游戏结果来创建相同的数据？

感谢。

id | game | team1     | team2     | score1 | score2 | gameset | diff
--------------------------------------------------------------------
1  | 1    | Reagan    | Jefferson | 43     | 48     | 0       | -5      
2  | 1    | Jefferson | Reagan    | 48     | 43     | 1       |  5

-

id | team       | win | loss | PF | PA | diff
-----------------------------------------------
1  | Jefferson  | 1   | 0    | 48 | 43 |  5
2  | Reagan     | 0   | 1    | 43 | 48 | -5

SQL CODE：

$sql = 'SELECT id, team1, Sum(diff) as tdiff,
               Sum(If(score1>score2,2,0)) + Sum(If(score1=score2,1,0)) +
                   Sum(If(score1+score2=0,-1,0)) AS Pts, 
               Sum(If(score1>score2,1,0)) AS Wins, 
               Sum(If(score1<score2,1,0)) AS Losses, 
               Sum(If(score1+score2=0,-1,0)) + Sum(If(score1=score2,1,0)) AS Ties,
               Sum(score2) AS Allowed, Sum(score1) AS Scored
          FROM database
      GROUP BY team1 ORDER BY Pts DESC, Allowed ASC, Scored DESC, team1 ASC';

Answer 1

您可以使用两个查询的UNION执行此操作。但是，我不清楚结果中id列应该是什么，所以我把它排除了。赢得2分，平局1分，亏损0分是不是更常见的？你的公式似乎没有得分没有得分。 UNION指定两个分数，即“团队得分”或t_score，以及“对手得分”或o_score。它有效地为database表中的每一行创建了两行（更常规地命名为game_results - 'database'应该保留用于表的集合，而不是单个表。） / p>

SELECT team, SUM(diff) AS tdiff,
       SUM(IF(t_score > o_score, 2, 0)) +
           SUM(IF(t_score = o_score, 1, 0)) +
           SUM(IF(t_score + o_score =0, -1, 0)) AS Pts, 
       SUM(IF(t_score > o_score, 1, 0)) AS Wins, 
       SUM(IF(t_score < o_score, 1, 0)) AS Losses, 
       SUM(IF(t_score + o_score = 0, -1, 0)) +
           SUM(IF(t_score = o_score, 1, 0)) AS Ties,
       SUM(o_score) AS Allowed,
       SUM(t_score) AS Scored
  FROM (SELECT team1 AS team, game, 'H' AS home_away,
               score1 AS t_score, score2 AS o_score
          FROM database
        UNION ALL
        SELECT team2 AS team, game, 'A' AS home_away,
               score2 AS t_score, score1 AS o_score
          FROM database
       ) AS R 
  GROUP BY team ORDER BY Pts DESC, Allowed ASC, Scored DESC, team ASC;

Answer 2

这完全是我需要的乔纳森！让我走上正轨并开始工作！更新后的代码如下

SELECT团队，SUM（t_score-o_score）为tdiff，
       SUM（IF（t_score＆gt; o_score，2,0））+
       SUM（IF（t_score = o_score，1,0））+
       SUM（IF（t_score + o_score = 0，-1,0））AS Pts，
       SUM（IF（t_score＆gt; o_score，1,0））AS Wins，
       SUM（IF（t_score＆lt; o_score，1,0））AS损失，
       SUM（IF（t_score + o_score = 0，-1,0））+
       SUM（IF（t_score = o_score，1,0））AS Ties，
       SUM（o_score）AS允许，
       SUM（t_score）AS得分
       FROM（SELECT id，diff，team1 AS team，game，'H'AS home_away，
       得分1 AS t_score，得分2 AS o_score
       来自mn_alldistrictgames
       UNION ALL
       SELECT id，diff，team2 AS团队，游戏，'A'AS home_away，
       得分2 AS t_score，得分1 AS o_score
       来自mn_alldistrictgames
       ）AS R
  GROUP BY团队ORDER BY Pts DESC，允许ASC，得分DESC，ASC团队

小组和总和分数 - 关于这个的任何想法？

2 个答案: