Question

我有一个数组输出是这样的：

Array ( [winners] => 
Array ( [0] => Gold Member 
        [1] => CROTCH SNIFFER 
        [2] => TEAM #1 )         
        [prizeTotal] => 20 )

Array ( [winners] => 
Array ( [0] => TEAM #1  
        [1] => CROTCH SNIFFER )
        [prizeTotal] => 60 ) 

Array ( [winners] => 
Array ( [0] => Gold Member 
        [1] => TEAM #1 ) 
        [prizeTotal] => 30 )

Array ( [winners] => 
Array ( [0] => TEAM #1 
        [1] => TEAM #2
        [2] => SCREW-NUT-BOLT )
        [prizeTotal] => 90 )

请原谅名字......这不是我的DB。
我无法改变数组显示的方式。

据说有什么可以分组和总结？ 1.对于每个获胜者阵列，奖项总数低于团队名称。该奖金总额应该是其上方每个teamName的值。

实施例

Array ( [winners] => 
Array ( [0] => Gold Member 
        [1] => CROTCH SNIFFER 
        [2] => TEAM #1 )         
        [prizeTotal] => 20 )
Gold Member should have 20
CROTCH SNIFFER should have 20
TEAM #1 should have 20 AND

Array ( [winners] => 
Array ( [0] => TEAM #1  
        [1] => CROTCH SNIFFER )
        [prizeTotal] => 60 ) 
TEAM #1 should have 60
CROTCH SNIFFER sould have 60....etc....

然后我想按团队名称和总和分组，以便我可以显示......

CROTCH SNIFFER = 80 金牌会员= 50 团队＃1 = 200 团队＃2 = 90。

提前致谢...

Answer 1

假设您可以将所有数组收集到一个，即：

$arrays = array($array1,$array2,....,$arrayn);

然后

$grouping = array();

foreach($arrays AS $array)
{
   foreach($array['winners'] AS $k=>$v)
   {
      //check if the array key is a number, will contain a team, and if that
      //them is not alreay listed
      if(is_numeric($k) && !array_key_exists($v,$grouping))
         $grouping[$v] = 0;
      //sum the prize to the team's sum
      $grouping[$v] += intval($array['winners']['prizeTotal']);
   }
}
//the following is just for debugging
print_r($grouping);

这应该产生类似的东西：

$grouping[TEAM #1] = 200
$grouping[TEAM #2] = 90
$grouping[CROTCH SNIFFER] = 200
...

Answer 2

您需要创建一个新数组来保存结果，然后对于每个现有数组，检查您是否已经为该团队处理了一个

如果有，则只需将prizeTotal添加到存储在该阵容的新阵列条目中的prizeTotal。

如果没有，只需将团队的条目添加到新阵列。

Answer 3

我创建了一个模仿mysql SUM()和GROUP BY的函数。我希望它能满足您的需求：

           $in_a = array(
                array("a" => 0,"b"=>0,"s"=> 1),
                array("a" => 0,"b"=>0,"s"=> 2),
                array("a" => 1,"b"=>1,"s"=> 1),
                array("a" => 0,"b"=>1,"s"=> 1),
                array("a" => 0,"b"=>1,"s"=> 1),
                array("a" => 1,"b"=>0,"s"=> 1),         
                array("a" => 0,"b"=>1,"s"=> 1),         
                array("a" => 1,"b"=>1,"s"=> 1),         
                array("a" => 1,"b"=>0,"s"=> 1),         
            );//input array exaple
            $group_by_a = array("a","b");//input array will be grouped by these
            $sum_a = array("s"); //'s' values of input will be summed
            $out_a = array(); //this is the output array

            foreach($in_a as $in_i => $in)
            {
                $add = false;
                foreach($out_a as $out_i => $out)
                {
                    $add = true;
                    foreach($group_by_a as $group_by)
                        if($in[$group_by] != $out[$group_by])
                        {
                            $add = false; 
                            break;
                        }                   
                    if($add)
                    {
                        foreach($sum_a as $sum)
                            $out_a[$out_i][$sum] += $in[$sum];  
                        break;
                    }
                }
                if(!$add)
                {
                    foreach($group_by_a as $group_by)
                        $out_a[$in_i][$group_by] = $in[$group_by];
                    foreach($sum_a as $sum)
                        $out_a[$in_i][$sum] = $in[$sum];                    
                }                   
            }

结果：

Array
(
    [0] => Array
        (
            [a] => 0
            [b] => 0
            [s] => 3
        )

    [2] => Array
        (
            [a] => 1
            [b] => 1
            [s] => 2
        )

    [3] => Array
        (
            [a] => 0
            [b] => 1
            [s] => 3
        )

    [5] => Array
        (
            [a] => 1
            [b] => 0
            [s] => 2
        )

)

对此数组进行分组和求和

3 个答案: