XSLT列出了多个值

时间:2012-06-19 10:41:49

标签: xml xslt xpath

我有类似于此的XML(为简洁起见省略了部分):

  <uformrecord>
      <state>Submitted</state>
      <created>2012-06-19T11:31:54</created>
      <updated>2012-06-19T11:32:13</updated>
      <id>53225sas3c1-d727-42cd-93a6-97cd778e5ee9</id>
      <ip>123.45.3.60</ip>
      <pageid url="/blah.aspx" name="Vacancy Application">1873</pageid>
      <memberkey emaillogin=""></memberkey>
      <fields>

        <ifyouhavetickedyeshowwouldyoudescribeyourdisabilitytickallthatapplytoyou record="532253c1-d727-42cd-93a6-97cd778e5ee9" sortorder="1" pageindex="2" fieldsetindex="0">
          <key>73b9150d-c65c-4ec0-9c8f-8d334b0495bf</key>
          <fieldKey>07a8ade7-ae13-41e6-bc3a-fe8444bcf9b0</fieldKey>
          <caption>If you have ticked 'Yes', how would you describe your disability (Tick all that apply to you.)</caption>
          <datatype>String</datatype>
          <values>
            <value key="c6de1932-9bba-4691-b19e-a44b5bb68c6c">I have a hearing problem</value>
            <value key="dd902bdb-89d7-4f14-ab60-4e69e803f321">I use a wheelchair</value>
            <value key="322c8e15-f722-406c-9d10-1769a2fb306e">I am dyslexic</value>
          </values>
        </ifyouhavetickedyeshowwouldyoudescribeyourdisabilitytickallthatapplytoyou>

      </fields>
    </uformrecord>

我正在申请xslt并做类似的事情:

<xsl:choose>
        <xsl:when test="$records//fields/ifyouhavetickedyeshowwouldyoudescribeyourdisabilitytickallthatapplytoyou//value != ''">

     <xsl:value-of select="$records//fields/ifyouhavetickedyeshowwouldyoudescribeyourdisabilitytickallthatapplytoyou//value"/>

        </xsl:when>
        <xsl:otherwise>
          NO DISABILITIES MENTIONED
        </xsl:otherwise>
      </xsl:choose>

这只输出第一个值('我有听力问题')

如何让它列出所有值?

2 个答案:

答案 0 :(得分:1)

未经测试(将长节点名称替换为“longname”)...

<xsl:for-each select="$records//fields/longname//value">
  <xsl:value-of select="."/>
</xsl:for-each>
<xsl:if test="not($records//fields/longname//value)">
  NO DISABILITIES MENTIONED
</xsl:if>

修改

我已经更新了上述内容,因为我认为!= ''是不必要的

答案 1 :(得分:1)

如果您将代码作为XSLT 2.0样式表运行,您的代码将输出所有值:XSLT 2.0更改了xsl:value-of的行为,因此它输出所有值,而不仅仅是第一个。