我有类似于此的XML(为简洁起见省略了部分):
<uformrecord>
<state>Submitted</state>
<created>2012-06-19T11:31:54</created>
<updated>2012-06-19T11:32:13</updated>
<id>53225sas3c1-d727-42cd-93a6-97cd778e5ee9</id>
<ip>123.45.3.60</ip>
<pageid url="/blah.aspx" name="Vacancy Application">1873</pageid>
<memberkey emaillogin=""></memberkey>
<fields>
<ifyouhavetickedyeshowwouldyoudescribeyourdisabilitytickallthatapplytoyou record="532253c1-d727-42cd-93a6-97cd778e5ee9" sortorder="1" pageindex="2" fieldsetindex="0">
<key>73b9150d-c65c-4ec0-9c8f-8d334b0495bf</key>
<fieldKey>07a8ade7-ae13-41e6-bc3a-fe8444bcf9b0</fieldKey>
<caption>If you have ticked 'Yes', how would you describe your disability (Tick all that apply to you.)</caption>
<datatype>String</datatype>
<values>
<value key="c6de1932-9bba-4691-b19e-a44b5bb68c6c">I have a hearing problem</value>
<value key="dd902bdb-89d7-4f14-ab60-4e69e803f321">I use a wheelchair</value>
<value key="322c8e15-f722-406c-9d10-1769a2fb306e">I am dyslexic</value>
</values>
</ifyouhavetickedyeshowwouldyoudescribeyourdisabilitytickallthatapplytoyou>
</fields>
</uformrecord>
我正在申请xslt并做类似的事情:
<xsl:choose>
<xsl:when test="$records//fields/ifyouhavetickedyeshowwouldyoudescribeyourdisabilitytickallthatapplytoyou//value != ''">
<xsl:value-of select="$records//fields/ifyouhavetickedyeshowwouldyoudescribeyourdisabilitytickallthatapplytoyou//value"/>
</xsl:when>
<xsl:otherwise>
NO DISABILITIES MENTIONED
</xsl:otherwise>
</xsl:choose>
这只输出第一个值('我有听力问题')
如何让它列出所有值?
答案 0 :(得分:1)
未经测试(将长节点名称替换为“longname”)...
<xsl:for-each select="$records//fields/longname//value">
<xsl:value-of select="."/>
</xsl:for-each>
<xsl:if test="not($records//fields/longname//value)">
NO DISABILITIES MENTIONED
</xsl:if>
修改强>
我已经更新了上述内容,因为我认为!= ''
是不必要的
答案 1 :(得分:1)
如果您将代码作为XSLT 2.0样式表运行,您的代码将输出所有值:XSLT 2.0更改了xsl:value-of的行为,因此它输出所有值,而不仅仅是第一个。